Concept explainers
(a)
Interpretation:
The identical, enantiomer, diastereomer or constitutional isomers for the given compound has to be identified from the given pairs of each compound.
Concept introduction:
Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.
The interchanging the solid-hatched wedge line of two groups of asymmetric centers will give different configuration.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
The pair of Enantiomers non-superimposable mirror images of each other.
(b)
Interpretation:
The identical, enantiomer, diastereomer or constitutional isomers for the given compound has to be identified from the given pairs of each compound.
Concept introduction:
Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.
The interchanging the solid-hatched wedge line of two groups of asymmetric centers will give different configuration.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
The pair of Enantiomers non-superimposable mirror images of each other.
(c)
Interpretation:
The identical, enantiomer, diastereomer or constitutional isomers for the given compound has to be identified from the given pairs of each compound.
Concept introduction:
Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.
The interchanging the solid-hatched wedge line of two groups of asymmetric centers will give different configuration.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
The pair of Enantiomers non-superimposable mirror images of each other.
(d)
Interpretation:
The identical, enantiomer, diastereomer or constitutional isomers for the given compound are to be identified from the given pairs of each compound.
Concept introduction:
Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter.
The interchanging the solid-hatched wedge line of two groups of asymmetric centers will give different configuration.
Diastereomers are stereoisomers which are neither mirror images nor identical. If two stereoisomers are not enantiomers, then they are Diastereomers.
The pair of Enantiomers non-superimposable mirror images of each other.
Constitutional isomers have same molecular formula but different structural formula or bond connectivity.
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Chapter 4 Solutions
Organic Chemistry
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- Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…arrow_forwardPropose a synthesis pathway for the following transformations. b) c) d)arrow_forwardThe rate coefficient of the gas-phase reaction 2 NO2 + O3 → N2O5 + O2 is 2.0x104 mol–1 dm3 s–1 at 300 K. Indicate whether the order of the reaction is 0, 1, or 2.arrow_forward
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- In the drawing area below, draw the major products of this organic reaction: 1. NaOH ? 2. CH3Br If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. No reaction. Click and drag to start drawing a structure. ☐ : A คarrow_forwardPredict the major products of the following organic reaction: NC Δ ? Some important Notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to draw bonds carefully to show important geometric relationships between substituents. Note: if your answer contains a complicated ring structure, you must use one of the molecular fragment stamps (available in the menu at right) to enter the ring structure. You can add any substituents using the pencil tool in the usual way. Click and drag to start drawing a structure. Х аarrow_forwardPredict the major products of this organic reaction. Be sure you use dash and wedge bonds to show stereochemistry where it's important. + ☑ OH 1. TsCl, py .... 文 P 2. t-BuO K Click and drag to start drawing a structure.arrow_forward
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