The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained. Concept introduction: Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers. Enantiomers are stereoisomers, in which they are mirror images of each other. Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups. If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist. The bond angle of cyclopropane is 60 ∘ .

Question

Want to see the full answer?

Answer 1

Question

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Which of the following is true for a particular reaction if ∆G° is -40.0 kJ/mol at 290 K and –20.0 kJ/mol at 390 K?

What is the major product of the following reaction? O O OH OH 1. BH 2. H₂O₂, NaOH OH OH

Draw the products formed when each ester is hydrolyzed with water and sulfuric acid.

Answer 2

Question

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Answer 6

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Answer 7

Chapter 4, Problem 78P

Interpretation Introduction

Interpretation:

The reason why the given enantiomers of a compound can be separated even though the one of the group attached to nitrogen is a lone pair has to be explained.

Concept introduction:

Stereoisomers are isomers which have different spatial arrangement in spite of same bond connectivity. Stereoisomers are due to the presence of stereocenter. Stereocenter may be an atom axis (bond) or plane from which interchanging of two groups leads to stereoisomers.

Enantiomers are stereoisomers, in which they are mirror images of each other.

Asymmetric center is a stereocenter which arises to a compound if any atom is bonded to four different groups.

If one of the four groups attached to nitrogen is lone pair, then inversion of amine takes place for acyclic amines easily. So stereoisomers will not exist.

The bond angle of cyclopropane is 60∘.

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 4.1 - Prob. 2P Ch. 4.1 - Prob. 3P Ch. 4.1 - Prob. 4P Ch. 4.1 - Prob. 5P Ch. 4.1 - Which of the roll owing compounds have a dipole...Ch. 4.2 - Prob. 7P Ch. 4.3 - Prob. 8P Ch. 4.4 - Prob. 10P Ch. 4.4 - Prob. 11P Ch. 4.6 - Prob. 12P

Want to see the full answer?

Chapter 4 Solutions