a. Explanation Given information: The below table is the measured weight ( in tons ) and fuel economy ( in mpg ) for a sample of seven trucks. W e i g h t ( x ) 8.00 24.50 27.00 14.50 28.50 12.75 21.25 M i l e a g e ( y ) 7.69 4.97 4.56 6.49 4.34 6.24 4.45 Concept Used: The correlation coefficient is given as, r = 1 n − 1 ∑ ( x − x ¯ s x ) ( y − y ¯ s y ) Where, n is the number of observations x ¯ is the average of x y ¯ is the average of y s x is the standard deviation of x s y is the standard deviation of y Calculation: Here, x = weight and y = mileage n = 7 x ¯ = 19.5 y ¯ = 5.53429 s x = 7.83289 s y = 1.28635 Weight 8 24.5 27 14.5 28.5 12.75 21 b. To determine To calculate: The coefficient of determination. c. To determine To calculate: The variation in mileage explained by the least-square regression line.

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ISBN: 9780077836351

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Chapter 4, Problem 4RE

To determine

To calculate: The correlation coefficient between weight and mileage.

To determine

To calculate: The coefficient of determination.

To determine

To calculate: The variation in mileage explained by the least-square regression line.

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The correlation coefficient between weight and mileage.

Solution Summary: The author calculates the correlation coefficient between weight and mileage.

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To calculate: The correlation coefficient between weight and mileage.

To calculate: The coefficient of determination.

To calculate: The variation in mileage explained by the least-square regression line.

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Chapter 4 Solutions