The initial voltage across the capacitor shown in Figure P4.3 is
Figure P4.3
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- Suppose that we have a 1000-pF parallel-plate capacitor with air dielectric charged to 1000 V. The capacitor terminals are open circuited. Find the stored energy. If the plates are moved farther apart so that d is doubled, determine the new voltage on the capacitor and the new stored energy. Where did the extra energy come from?arrow_forwardA capacitor can be used .............................................. in electrical circuits. Which of the followings fit? To regulate the currents To regulate the voltages To store energy by deposition of electric charges To provide energy as passive circuit element To store energy in the form of magnetic field To create time varying voltages and currents To dissipate energy To convert elektrik energy into heat or lightarrow_forwardAt 0-, no currrent flows through the capacitors because they are open, how did you combine the capacitors for the voltage divider since it is the capacitance value and not reactance, is it right? Can we just combine the capacitance value? Please explain. I did not understand..arrow_forward
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