Two teams will play a series of games, with the winner being the first team to win a total of 4 games. Suppose that, independently of earlier results, team 1 wins each game it plays with probability 0 < p < 1 .Let N denote the number of games that are played. a. Show that P ( N = 6 ) ≥ P ( N = 7 ) with equality only when p = 1 2 . b. Give an intuitive explanation for why equality results when p = 1 2 . Hint: Consider what needs to be true in order for the number of games to be either 6 or 7. c. If p = 1 2 , find the probability that the team that wins the first game wins the series.
Two teams will play a series of games, with the winner being the first team to win a total of 4 games. Suppose that, independently of earlier results, team 1 wins each game it plays with probability 0 < p < 1 .Let N denote the number of games that are played. a. Show that P ( N = 6 ) ≥ P ( N = 7 ) with equality only when p = 1 2 . b. Give an intuitive explanation for why equality results when p = 1 2 . Hint: Consider what needs to be true in order for the number of games to be either 6 or 7. c. If p = 1 2 , find the probability that the team that wins the first game wins the series.
Solution Summary: The author explains how the random variable X is different from a negative binomial random variables. Balls are randomly withdrawn from an urn containing n white and m black balls.
Two teams will play a series of games, with the winner being the first team to win a total of 4 games. Suppose that, independently of earlier results, team 1 wins each game it plays with probability
0
<
p
<
1
.Let N denote the number of games that are played.
a. Show that
P
(
N
=
6
)
≥
P
(
N
=
7
)
with equality only when
p
=
1
2
.
b. Give an intuitive explanation for why equality results when
p
=
1
2
.
Hint: Consider what needs to be true in order for the number of games to be either 6 or 7.
c. If
p
=
1
2
, find the probability that the team that wins the first game wins the series.
Q1. A group of five applicants for a pair of identical jobs consists of three men and two
women. The employer is to select two of the five applicants for the jobs. Let S
denote the set of all possible outcomes for the employer's selection. Let A denote
the subset of outcomes corresponding to the selection of two men and B the subset
corresponding to the selection of at least one woman. List the outcomes in A, B,
AUB, AN B, and An B. (Denote the different men and women by M₁, M2, M3
and W₁, W2, respectively.)
Q3 (8 points)
Q3. A survey classified a large number of adults according to whether they were diag-
nosed as needing eyeglasses to correct their reading vision and whether they use
eyeglasses when reading. The proportions falling into the four resulting categories
are given in the following table:
Use Eyeglasses for Reading
Needs glasses Yes
No
Yes
0.44
0.14
No
0.02
0.40
If a single adult is selected from the large group, find the probabilities of the events
defined below. The adult
(a) needs glasses.
(b) needs glasses but does not use them.
(c) uses glasses whether the glasses are needed or not.
4. (i) Let a discrete sample space be given by
N = {W1, W2, W3, W4},
and let a probability measure P on be given by
P(w1) = 0.2, P(w2) = 0.2, P(w3) = 0.5, P(wa) = 0.1.
Consider the random variables X1, X2 → R defined by
X₁(w1) = 1, X₁(w2) = 2,
X2(w1) = 2, X2 (w2) = 2,
Find the joint distribution of X1, X2.
(ii)
X1(W3) = 1, X₁(w4) = 1,
X2(W3) = 1, X2(w4) = 2.
[4 Marks]
Let Y, Z be random variables on a probability space (, F, P).
Let the random vector (Y, Z) take on values in the set [0, 1] x [0,2] and let the
joint distribution of Y, Z on [0, 1] x [0,2] be given by
1
dPy,z (y, z) ==(y²z+yz2) dy dz.
harks 12 Find the distribution Py of the random variable Y.
[8 Marks]
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.
Discrete Distributions: Binomial, Poisson and Hypergeometric | Statistics for Data Science; Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=lHhyy4JMigg;License: Standard Youtube License