Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Chapter 4, Problem 26E
Interpretation Introduction

(a)

Interpretation:

The diagram that represents the arrangement of protons, neutrons, and electrons in 1531P is to be drawn.

Concept introduction:

An atom is made up of three subatomic particles, which are neutrons, protons, and electrons. Neutron and protons are present in the nucleus of the atom, whereas electrons are revolving outside the nucleus in an atom. Isotopes are those atoms that have the same number of protons but a different number of neutrons.

Expert Solution
Check Mark

Answer to Problem 26E

The diagram that represents the arrangement of protons, neutrons, and electrons in 1531P is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  1

Explanation of Solution

The atomic mass of 1531P is 31.

The atomic number of 1531P is 15.

The number of electrons and number of protons in a neutral atom is equal to its atomic number. Hence, the number of protons and number of electrons present in 1531P is 15.

The atomic mass of the element is represented by the formula as shown below.

A=Np+Nn…(1)

Where,

Np represent the number of protons present in the atom.

Nn represent the number of neutrons present in the atom.

Rearrange the above equation for the value of Nn.

Nn=Np+A

Substitute the value of A and Np in the equation (1).

Nn=3115=16

One atom of 1531P has 15 protons, 15 electrons, and 16 neutrons.

Therefore, the diagram that represents the arrangement of protons, neutrons, and electrons in 1531P is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  2

Figure 1

Conclusion

The diagram that represents the arrangement of protons, neutrons, and electrons in 1531P is shown in Figure 1.

Interpretation Introduction

(b)

Interpretation:

The diagram that represents the arrangement of protons, neutrons, and electrons in 1735Cl is to be drawn.

Concept introduction:

An atom is made up of three subatomic particles, which are neutrons, protons, and electrons. Neutron and protons are present in the nucleus of the atom, whereas electrons are revolving outside the nucleus in an atom. Isotopes are those atoms that have the same number of protons but a different number of neutrons.

Expert Solution
Check Mark

Answer to Problem 26E

The diagram that represents the arrangement of protons, neutrons, and electrons in 1735Cl is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  3

Explanation of Solution

The atomic mass of 1735Cl is 35.

The atomic number of C1735l is 17.

The number of electrons and number of protons in a neutral atom is equal to its atomic number. Hence, the number of protons and number of electrons present in C1735l is 17.

The atomic mass of the element is represented by the formula as shown below.

A=Np+Nn…(1)

Where,

Np represent the number of protons present in the atom.

Nn represent the number of neutrons present in the atom.

Rearrange the above equation for the value of Nn.

Nn=Np+A

Substitute the value of A and Np in the equation (1).

Nn=3517=18

One atom of C1735l has 17 protons, 17 electrons, and 18 neutrons.

Therefore, the diagram that represents the arrangement of protons, neutrons, and electrons in C1735l is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  4

Figure 2

Conclusion

The diagram that represents the arrangement of protons, neutrons, and electrons in C1734l is shown in Figure 2.

Interpretation Introduction

(c)

Interpretation:

The diagram that represents the arrangement of protons, neutrons, and electrons in 1840Ar is to be drawn.

Concept introduction:

An atom is made up of three subatomic particles, which are neutrons, protons, and electrons. Neutron and protons are present in the nucleus of the atom, whereas electrons are revolving outside the nucleus in an atom. Isotopes are those atoms that have the same number of protons but a different number of neutrons.

Expert Solution
Check Mark

Answer to Problem 26E

The diagram that represents the arrangement of protons, neutrons, and electrons in 1840Ar is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  5

Explanation of Solution

The atomic mass of 1840Ar is 40.

The atomic number of 1840Ar is 18.

The number of electrons and number of protons in a neutral atom is equal to its atomic number. Hence, the number of protons and number of electrons present in 1840Ar is 18.

The atomic mass of the element is represented by the formula as shown below.

A=Np+Nn…(1)

Where,

Np is the number of protons present in the atom.

Nn is the number of neutrons present in the atom.

Rearrange the above equation for the value of Nn.

Nn=Np+A

Substitute the value of A and Np in the equation (1).

Nn=4018=22

One atom of 1840Ar has 18 protons, 18 electrons, and 22 neutrons.

Therefore, the diagram that represents the arrangement of protons, neutrons, and electrons in 1840Ar is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  6

Figure 3

Conclusion

The diagram that represents the arrangement of protons, neutrons, and electrons in 1840Ar is shown in Figure 3.

Interpretation Introduction

(d)

Interpretation:

The diagram that represents the arrangement of protons, neutrons, and electrons in 53131I is to be drawn.

Concept introduction:

An atom is made up of three subatomic particles-neutrons, protons, and electrons. Neutron and protons are present in the nucleus of the atom, whereas electrons are revolving outside the nucleus in an atom. Isotopes are those atoms that have the same number of protons but a different number of neutrons.

Expert Solution
Check Mark

Answer to Problem 26E

The diagram that represents the arrangement of protons, neutrons, and electrons in 53131I is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  7

Explanation of Solution

The atomic mass of 53131I is 131.

The atomic number of 53131I is 53.

The number of electrons and number of protons in a neutral atom is equal to its atomic number. Hence, the number of protons and number of electrons present in 53131I is 53.

The atomic mass of the element is represented by the formula as shown below.

A=Np+Nn…(1)

Where,

Np represent the number of protons present in the atom.

Nn represent the number of neutrons present in the atom.

Rearrange the above equation for the value of Nn.

Nn=Np+A

Substitute the value of A and Np in the equation (1).

Nn=13153=78

One atom of 53131I has 53 protons, 53 electrons, and 78 neutrons.

Therefore, the diagram that represents the arrangement of protons, neutrons, and electrons in 53131I is shown below.

Introductory Chemistry: Concepts and Critical Thinking (8th Edition), Chapter 4, Problem 26E , additional homework tip  8

Figure 4

Conclusion

The diagram that represents the arrangement of protons, neutrons, and electrons in 53131I is shown in Figure 4.

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Chapter 4 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 4 - Prob. 11CECh. 4 - Prob. 12CECh. 4 - Prob. 1KTCh. 4 - Prob. 2KTCh. 4 - Prob. 3KTCh. 4 - Prob. 4KTCh. 4 - Prob. 5KTCh. 4 - Prob. 6KTCh. 4 - Prob. 7KTCh. 4 - Prob. 8KTCh. 4 - Prob. 9KTCh. 4 - Prob. 10KTCh. 4 - Prob. 11KTCh. 4 - Prob. 12KTCh. 4 - Prob. 13KTCh. 4 - Prob. 14KTCh. 4 - Prob. 15KTCh. 4 - Prob. 16KTCh. 4 - Prob. 17KTCh. 4 - Prob. 18KTCh. 4 - Prob. 19KTCh. 4 - Prob. 20KTCh. 4 - Prob. 21KTCh. 4 - Prob. 22KTCh. 4 - Prob. 23KTCh. 4 - Prob. 24KTCh. 4 - Prob. 25KTCh. 4 - Prob. 1ECh. 4 - Prob. 2ECh. 4 - Prob. 3ECh. 4 - Prob. 4ECh. 4 - Prob. 5ECh. 4 - Prob. 6ECh. 4 - Prob. 7ECh. 4 - Prob. 8ECh. 4 - Prob. 9ECh. 4 - Prob. 10ECh. 4 - Prob. 11ECh. 4 - Prob. 12ECh. 4 - Prob. 13ECh. 4 - Prob. 14ECh. 4 - Prob. 15ECh. 4 - Prob. 16ECh. 4 - Prob. 17ECh. 4 - Prob. 18ECh. 4 - Prob. 19ECh. 4 - Prob. 20ECh. 4 - Prob. 21ECh. 4 - Prob. 22ECh. 4 - Prob. 23ECh. 4 - Prob. 24ECh. 4 - Prob. 25ECh. 4 - Prob. 26ECh. 4 - Prob. 27ECh. 4 - Prob. 28ECh. 4 - Prob. 29ECh. 4 - Prob. 30ECh. 4 - Prob. 31ECh. 4 - Prob. 32ECh. 4 - Prob. 33ECh. 4 - Prob. 34ECh. 4 - Prob. 35ECh. 4 - Prob. 36ECh. 4 - Prob. 37ECh. 4 - Prob. 38ECh. 4 - Prob. 39ECh. 4 - Prob. 40ECh. 4 - Prob. 41ECh. 4 - Prob. 42ECh. 4 - Prob. 43ECh. 4 - Prob. 44ECh. 4 - Prob. 45ECh. 4 - Prob. 46ECh. 4 - Prob. 47ECh. 4 - Prob. 48ECh. 4 - Prob. 49ECh. 4 - Prob. 50ECh. 4 - Prob. 51ECh. 4 - Prob. 52ECh. 4 - Prob. 53ECh. 4 - Prob. 54ECh. 4 - Prob. 55ECh. 4 - Prob. 56ECh. 4 - Prob. 57ECh. 4 - Prob. 58ECh. 4 - Prob. 59ECh. 4 - Prob. 60ECh. 4 - Prob. 61ECh. 4 - Prob. 62ECh. 4 - Prob. 63ECh. 4 - Prob. 64ECh. 4 - Prob. 65ECh. 4 - Prob. 66ECh. 4 - Prob. 67ECh. 4 - Prob. 68ECh. 4 - Prob. 69ECh. 4 - Prob. 70ECh. 4 - Prob. 71ECh. 4 - Prob. 72ECh. 4 - Prob. 73ECh. 4 - Prob. 74ECh. 4 - Prob. 75ECh. 4 - Prob. 76ECh. 4 - Prob. 77ECh. 4 - Prob. 78ECh. 4 - Prob. 79ECh. 4 - Prob. 80ECh. 4 - Prob. 81ECh. 4 - Prob. 82ECh. 4 - Prob. 83ECh. 4 - Prob. 84ECh. 4 - Prob. 85ECh. 4 - Prob. 86ECh. 4 - Prob. 87ECh. 4 - Prob. 88ECh. 4 - Prob. 89ECh. 4 - Prob. 90ECh. 4 - Prob. 91ECh. 4 - Prob. 92ECh. 4 - Prob. 93ECh. 4 - Prob. 94ECh. 4 - Prob. 95ECh. 4 - Prob. 96ECh. 4 - Prob. 97ECh. 4 - Prob. 98ECh. 4 - Prob. 1STCh. 4 - Prob. 2STCh. 4 - Prob. 3STCh. 4 - Prob. 4STCh. 4 - Prob. 5STCh. 4 - Prob. 6STCh. 4 - Prob. 7STCh. 4 - Prob. 8STCh. 4 - Prob. 9STCh. 4 - Prob. 10STCh. 4 - Prob. 11STCh. 4 - Prob. 12STCh. 4 - Prob. 13STCh. 4 - Prob. 14STCh. 4 - Prob. 15STCh. 4 - Prob. 16STCh. 4 - Prob. 17STCh. 4 - Prob. 18ST
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