Interpretation:
The
Concept Introduction:
An orbital is a region of space in which electrons are filled. It can hold up to two electrons.
An atomic orbital is the region of space in which the probability of finding the electrons is highest. It is subdivided into 4 orbitals such as
The orders in which orbitals are filled by the electrons are governed by three basic principles.
- 1. Aufbau principle: In the ground state of an atom, an electron enters the orbital with lowest energy first and subsequent electrons are fed in the order of increasing energies. The word 'aufbau' in German means 'building up'. Here, it refers to the filling up of orbitals with electrons.
- 2. Pauli exclusion principle: As an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.
- 3. Hund’s rule: Every orbital in a subshell is singly occupied with one electron before any one orbital is paired and all electrons in singly occupied orbitals have the same spin.
The electron configuration is the distribution of electrons of an atom in atomic orbitals. By following these three principles, electronic configuration of a particular atom is written.
To identify: The symbol of the element with the given ground-state electron configuration
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CHEMISTRY: ATOMS FIRST VOL 1 W/CONNECT
- (a) What is the hybridization of the carbon in the methyl cation (CH3*) and in the methyl anion (CH3¯)? (b) What is the approximate H-C-H bond angle in the methyl cation and in the methyl anion?arrow_forwardQ8: Draw the resonance structures for the following molecule. Show the curved arrows (how you derive each resonance structure). Circle the major resonance contributor.arrow_forwardQ4: Draw the Lewis structures for the cyanate ion (OCN) and the fulminate ion (CNO). Draw all possible resonance structures for each. Determine which form for each is the major resonance contributor.arrow_forward
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- Q2: Draw all applicable resonance forms for the acetate ion CH3COO. Clearly show all lone pairs, charges, and arrow formalism.arrow_forwardPlease correct answer and don't used hand raitingarrow_forward9. The following reaction, which proceeds via the SN1/E1 mechanisms, gives three alkene products (A, B, C) as well as an ether (D). (a) Show how each product arises mechanistically. (b) For the alkenes, determine the major product and justify your answer. (c) What clues in the reaction as shown suggest that this reaction does not go by the SN2/E2 mechanism route? (CH3)2CH-CH-CH3 CH3OH 1 Bl CH3OH ⑧· (CH3)2 CH-CH=CH2 heat H ⑥③ (CH3)2 C = C = CH3 © СнЗ-С-Снаснз сна (CH 3 ) 2 C H G H CH 3 оснзarrow_forward
- Please Don't used hand raitingarrow_forward7. For the following structure: ← Draw structure as is - NO BI H H Fisher projections (a) Assign R/S configuration at all chiral centers (show all work). Label the chiral centers with an asterisk (*). (b) Draw an enantiomer and diastereomer of the above structure and assign R/S configuration at all chiral centers (again, show all work). (c) On the basis of the R/S system, justify your designation of the structures as being enantiomeric or diastereomeric to the original structure.arrow_forwardDon't used Ai solutionarrow_forward
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