Concept explainers
(a)
The light intensity at the surface of the light bulb.
(a)
Answer to Problem 36.83AP
The light intensity at the surface of the light bulb is
Explanation of Solution
Given info:
The diameter of the spherical light bulb is
Formula to calculate the intensity at the surface of the light bulb is,
Here,
Substitute
Conclusion:
Therefore, the light intensity at the surface of the light bulb is
(b)
The light intensity at a distance
(b)
Answer to Problem 36.83AP
The light intensity at a distance
Explanation of Solution
Given info: The diameter of the spherical light bulb is
Formula to calculate the intensity at a distance
,
Here,
Substitute
Conclusion:
Therefore, the light intensity at a distance
(c)
The diameter of the light bulb image.
(c)
Answer to Problem 36.83AP
The diameter of the light bulb image is
Explanation of Solution
Given info: The diameter of the spherical light bulb is
From the lens maker formula,
Here,
Substitute
Thus, the image distance is
Formula to calculate the magnification of the image,
Here,
Formula to calculate the magnification of the image in terms of image and object distance is,
Here,
Equate the equation (1) and (2) and then rearrange for
Substitute
Conclusion:
Therefore, the diameter of the light bulb image is
(d)
The light intensity of the image.
(d)
Answer to Problem 36.83AP
The light intensity of the image is
Explanation of Solution
Given info: The diameter of the spherical light bulb is
From part (b) the light intensity at a distance
From part (c) the diameter of the light bulb image is
Formula to calculate the power of lens is,
Here,
The area of the lens is,
Substitute
The area of the lens is
Substitute
Formula to calculate the required intensity of bulb light image,
The area of image is,
Substitute
Substitute
Conclusion:
Therefore, the light intensity of the image is
Want to see more full solutions like this?
Chapter 36 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
- Light enters from air to glass having refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 × 108 m s-1.arrow_forwardVery short pulses of high intensity laser beams are used to repair detached portions of the retina of the eye. The brief pulses of energy absorbed by the retina welds the detached portion back into place. In one such procedure, a laser beam has a wavelength of 810 nm and delivers 250 mW of power spread over a circular spot 510 micrometers in diameter. The vitreous humor (the transparent fluid that fills most of the eye) has an index of refraction of 1.34. (A) what average pressure would the pulse of the laser beam exert at normal incidence on a surface in air if the beam is fully absorbed? (B) what is the wavelength of the laser light inside the vitreous humor of the eye? (C) what is the frequency of the laser light inside the vitreous humor of the eye?arrow_forwardSound waves undergo reflection and refraction, much as electromagnetic waves do. Here is one practical application of reflection and refraction in the field of health care: determining the location of a liver tumor. Suppose that a narrow beam of ultrasonic waves travels through surrounding tissue and enters the liver with an incidence angle of 51.0°. These inaudible sound waves travel 14.0% more slowly through the liver than through the medium that lies above. Suppose that the beam reflects off the tumor and emerges from the liver at a distance 13.0 cm from its entry point. Calculate the depth of the tumor (in cm) below the surface of the liver.arrow_forward
- Sound waves undergo reflection and refraction, much as electromagnetic waves do. Here is one practical application of reflection and refraction in the field of health care: determining the location of a liver tumor. Suppose that a narrow beam of ultrasonic waves travels through surrounding tissue and enters the liver with an incidence angle of 48.0°. These inaudible sound waves travel 11.5% more slowly through the liver than through the medium that lies above. Suppose that the beam reflects off the tumor and emerges from the liver at a distance 11.5 cm from its entry point. Calculate the depth of the tumor (in cm) below the surface of the liver.arrow_forwardA spherical source of light with a diameter Deource = 3.55 cm radiates light equally in all directions, with power P = 4.10 W. (a) Find the light intensity (in kW/m2) at the surface of the light source. |kW/m² (b) Find the light intensity (in mW/m2) r = 7.10 m away from the center of the light source. mW/m2 (c) At this 7.10 m distance, a lens is set up with its axis pointing toward the light source. The lens has a circular face with a diameter of Dlens = 16.0 cm and has a focal length of f = 34.0 cm. Find the diameter (in cm) of the light source's image. cm (d) Find the light intensity (in W/m2) at the image. |W/m2arrow_forwardLight with a frequency of 5.80 x 1014 Hz travels in a glass block with an index of refraction of 1.52. What is the wavelength of light? (a) in vacuum and (b) in the glass?arrow_forward
- The intensity L(x) of light x feet beneath the surface of the ocean satisfies the differential equation dL/dx=-kL. From experience, a diver knows that diving to 19 ft in a sea cuts the intensity in half. He cannot work without artifical light when the intensity falls below one-fifth of the surface value. About how deep can he expect to work without artifical light? round to the nearest tentharrow_forwardA light beam from a medium of refractive index 1 is incident normally on the vertical face of the prism as illustrated in the figure. The refractive index of the prism is 1.8. Find the maximum α for which no light leaves the prism through the inclined face and if within the medium the light has a frequency of 2.8 × 1014Hz, every how many meters is the undulating movement of this wave repeated within the prism?arrow_forwardThe speed of light in a vacuum is 3.00 ´ 108 m/s. If the refractive index of diamond is 2.42, what speed does light travel as it passes through a diamond?arrow_forward
- Light of wavelength 710 nm in vacuum passes through a piece of quartz of refractive index of 1.458. (a) Find the speed of light in quartz. (b) What is the wavelength of this light in quartz? Group of answer choices 6.02 x 108 m/s, 189 n m 2.06 x 108 m/s, 800 n m 2.06 x 108 m/s, 487 n m 2.06 x 108 m/s, 870 n marrow_forwardLight with a frequency of 5.80 * 10^14 Hz travels in a block of glass that has an index of refraction of 1.52. What is the wavelength of the light (a) in vacuum and (b) in the glass?arrow_forwardAn engineer, investigating the behavior of radio waves, builds a box 7.20 m long. Inside the box at one end is a small radio transmitter that emits radiation with a wavelength of 0.120 m. A receiver is placed at the other end, 7.20 m away. Assume both the transmitter and the receiver are on the floor of the box. The walls and floor of the box interior are treated to minimize reflection of radio waves. The ceiling of the box interior, however, is metal, so the radio waves can reflect off of it almost perfectly. The radio waves can take two paths from the transmitter to the receiver: a straight-line path, and a path that reflects off the ceiling of the box interior. Note that there is a phase shift when the waves reflect off the ceiling. (a) What is the minimum (nonzero) height of the box ceiling (in m) that could produce destructive interference between the direct and reflected waves at the receiver's location? (b) What If? Some modern Wi-Fi antennas emit frequencies in the 5 GHz band.…arrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-Hill