(a) Explanation Given info: The focal length of the lens in air is 79.0 cm , the index of refraction in air is 1.55 From the lens maker equation the focal length in air is, 1 f air = ( n − 1 ) ( 1 R 1 − 1 R 2 ) (1) Here, R 1 is the first radius of curvature. R 2 is the second radius of curvature. n is the index of refraction of air. Replace n by n 2 n 1 in the equation (1) to find the focal length of the water. 1 f water = ( n 2 n 1 − 1 ) ( 1 R 1 − 1 R 2 ) (2) Here, n 2 is refractive index of the air. n 1 is refractive index of the water. Divide the equation (1) and equation (2). 1 f air 1 f water = ( n − 1 ) ( 1 R 1 − 1 R 2 ) ( n 2 n 1 − 1 ) ( 1 < (b) To determine The focal length of the mirror in water.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 36, Problem 36.71AP

(a)

To determine

The focal length of the lens in water.

(b)

To determine

The focal length of the mirror in water.

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Chapter 36, Problem 36.70P

Chapter 36, Problem 36.72AP

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Chapter 36 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)

Ch. 36 - You are standing approximately 2 m away from a...Ch. 36 - You wish to start a fire by reflecting sunlight...Ch. 36 - Consider the image in the mirror in Figure 35.14....Ch. 36 - Prob. 36.4QQ Ch. 36 - Prob. 36.5QQ Ch. 36 - What is the focal length of a pane of window...Ch. 36 - A camera can be modeled as a simple converging...Ch. 36 - Two campers wish to start a fire during the day....Ch. 36 - The faceplate of a diving mask can be ground into...Ch. 36 - Lulu looks at her image in a makeup mirror. lt is...

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The focal length of the lens in water.

Solution Summary: The author explains the focal length of the lens in water. The index of retion in air is 1.55.

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