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Figure P35.20 (page 958) shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to Snell’s law, n1 sin θ1 = n2 sin θ2. For paraxial rays, we assume θ1, and θ2 are small, so we may write n1 tan θ1 = n2 tan θ2. The magnification is defined as M = h′/h. Prove that the magnification is given by M = −n1q/n2p.
Figure P35.20
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Chapter 36 Solutions
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- In Figure P35.30, a thin converging lens of focal length 14.0 cm forms an image of the square abed, which is he = hb = 10.0 cm high and lies between distances of pd = 20.0 cm and pa = 30.0 cm from the lens. Let a, b, c. and d represent the respective corners of the image. Let qa represent the image distance for points a and b, qd represent the image distance for points c and d, hb, represent the distance from point b to the axis, and hc represent the height of c. (a) Find qa, qd, hb, and hc. (b) Make a sketch of the image. (c) The area of the object is 100 cm2. By carrying out the following steps, you will evaluate the area of the image. Let q represent the image distance of any point between a and d, for which the object distance is p. Let h represent the distance from the axis to the point at the edge of the image between b and c at image distance q. Demonstrate that h=10.0q(114.01q) where h and q are in centimeters. (d) Explain why the geometric area of the image is given by qaqdhdq (e) Carry out the integration to find the area of the image. Figure P35.30arrow_forwardA Lucite slab (n = 1.485) 5.00 cm in thickness forms the bottom of an ornamental fish pond that is 40.0 cm deep. If the pond is completely filled with water, what is the apparent thickness of the Lucite plate when viewed from directly above the pond?arrow_forwardA light ray is incident on an interface between water (n = 1.333) and air (n = 1.0002926) from within the air. If the angle of incidence in the air is 30.0, what is the angle of the refracted ray in the water?arrow_forward
- How many times will the incident beam in Figure P34.33 (page 922) be reflected by each of the parallel mirrors? Figure P34.33arrow_forwardFigure P23.28 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I of object O. The ray shown in red passes through the surface along a radial line. Its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray shown in blue, the direction changes according to n1 sin 1 = n2 sin 2. For paraxial rays, we assume 1 and 2 are small, so we may write n1 tan 1 n2 tan 2. The magnification is defined as M = h/h. Prove that the magnification is given by M = n1q/n2p. Figure P23.28arrow_forwardA floating strawberry illusion is achieved with two parabolic mirrors, each having a focal length 7.50 cm, facing each other as shown in Figure P33.58. If a strawberry is placed on the lower mirror, an image of the strawberry is formed at the small opening at the center of the top mirror, 7.50 cm above the lowest point of the bottom mirror. The position of the eye in Figure P35.58a corresponds to the view of the apparatus in Figure P35.58b. Consider the light path marked A. Notice that this light path is blocked by the upper mirror so that the strawberry itself is not directly observable. The light path marked B corresponds to the eye viewing the image of the strawberry that is formed at the opening at the top of the apparatus. (a) Show that the final image is formed at that location and describe its characteristics. (b) A very startling effect is to shine a flashlight beam on this image. Even al a glancing angle, the incoming light beam is seemingly reflected from the image! Explain. Figure P35.58arrow_forward
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- The drawing shows a rectangular block of glass (n = 1.52) surrounded by a liquid with n = 1.75. A ray of light is incident on the glass at point A with a 30.0° angle of incidence. At what angle does the ray leave the glass at point B? Number i Units 4arrow_forwardChoose the correct statement regarding light traveling in air and glass mediums. Assume that the angle of incidence is not perpendicular to the surface. Refractive index of air is nair=1.00029; refractive index of glass is nglass=1.517. For light traveling from glass to air, the ray becomes bent toward the normal. O Light travels at a slower speed in air than in glass. For light traveling from air to glass, the ray becomes bent away from the normal. O For light traveling from air to glass, the incidence angle is larger than the refraction angle. O For light traveling from glass to air, the refraction angle is smaller than the incidence angle. Submit Answer Tries 0/2 Post Discussion Send Feedbaclarrow_forwardIn the figure below light begins in material 1 with index of refraction ng = 1.21 and makes an angle with the normal (dotted) line of 01= 34° as it strikes material 2. The light then refracts into material 2 with index of refraction n2 = 1.78 and unknown angle of refraction 02. Lastly, the light enters material 3 with unknown index of refraction ng and makes an angle 03= 26° with the normal line. What is the index of refraction of the bottom material n3? NOTE: Please enter your answer with three significant figures. Do not use scientific notation. Do not enter units (your answer is unitless).arrow_forward
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