(a) Explanation Given info: The series of parallel linear water wave fronts are travels directly towards the shore at 15.0 cm/s , a long concrete barrier that runs parallel to the shore at a distance of 3.20 m away as a hole on it, the number of wave crest in each minute is 75.0 , and it is observed that no waves reach the shore at ± 61.3 cm from the point directly opposite the hole. Formula to calculate the width of the slit for single slit diffraction is, sin θ 1 = λ a (I) θ 1 is the angle of diffraction of the first minima from the centre of the central maxima. λ is the wavelength of the wave. a is the width of the slit. Formula to calculate the wavelength of the water wave is, λ = v f v is the speed of the wave. f is the frequency of the wave. Substitute 15.0 cm/s for v and 75.0 min − 1 for f in the above equation to find λ . λ = 15.0 cm/s ( 75.0 min − 1 × 1 min 60 s ) = 12.0 cm Thus, the wavelength of the water wave is 12.0 cm . Formula to calculate the angle through which the first minima diffracted from the centre of the central maxima is (b) To determine The other angles at which no wave’s heats the shore.

University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

14th Edition

ISBN: 9780321982582

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Equation of Waves

Wave is an oscillation or disturbance traveling in a medium. It performs the transportation of energy but does not carry any matter. This motion of waves will transport fuel in a medium without permanent transfer of mass (particle).

Question

Chapter 36, Problem 36.7E

(a)

To determine

The width of the slit.

(b)

To determine

The other angles at which no wave’s heats the shore.

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Chapter 36, Problem 36.6E

Chapter 36, Problem 36.8E

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Chapter 36 Solutions

University Physics with Modern Physics Plus Mastering Physics with eText -- Access Card Package (14th Edition)

Ch. 36.1 - Can sound waves undergo diffraction around an...Ch. 36.2 - Rank the following single-slit diffraction...Ch. 36.3 - Coherent electromagnetic radiation is sent through...Ch. 36.4 - Suppose two slits, each of width a, are separated...Ch. 36.5 - What minimum number of slits would be required in...Ch. 36.6 - Prob. 36.6TYU Ch. 36.7 - Prob. 36.7TYU Ch. 36 - Why can we readily observe diffraction effects for...Ch. 36 - Prob. 36.2DQ Ch. 36 - You use a lens of diameter D and light of...

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