Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 3.6, Problem 18P

To determine

To find: the cost of each item − a carton of juice, a fruit cup, and a bowl of soup.

Expert Solution & Answer

Answer to Problem 18P

The cost of 1 carton of juice is 125 cents.

The cost of 1 bowl of soup is 175 cents.

The cost of 1 fruits cup is 225 cents.

Explanation of Solution

Given information:

Nine cartons of juice cost the same as 5 fruit cups. Also, one fruit cup costs 50 more than one bowl of soup, while one bowl of soup costs 50 more than one carton of juice.

Calculation:

Consider 1 carton of juice cost is x cents,

Then 50 cents more is x+50 is the cost of 1 bowl of soup,

And the cost of 1 fruits cup is x+50+50=x+100 ,

Nine cartons of juice cost is 9x ,

Five fruits cups cost is 5⋅(x+100)=5x+500 ,

Equate both values,

9x=5x+5004x=500 x=125

Therefore, 1 carton of juice cost is 125 cents,

The cost of 1 bowl of soup is x+50=125+50 =175

And the cost of 1 fruits cup is x+50+50=125+50+50 =225

Chapter 3.6, Problem 17P

Chapter 3.6, Problem 19P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 1OE Ch. 3.1 - Prob. 2OE Ch. 3.1 - Prob. 3OE Ch. 3.1 - Prob. 4OE Ch. 3.1 - Prob. 5OE Ch. 3.1 - Prob. 6OE Ch. 3.1 - Prob. 7OE Ch. 3.1 - Prob. 8OE Ch. 3.1 - Prob. 9OE Ch. 3.1 - Prob. 10OE

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