Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Concept explainers

Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
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Question
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Chapter 3, Problem 7CR
To determine

To calculate: how many hours does Howard spend waiting on customers

Expert Solution & Answer
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Answer to Problem 7CR

Howard spends 214 hours waiting on customers.

Explanation of Solution

Given information: Total working hours a day= 8 hours, Total hours to eat lunch and balance books= 114 , Ratio of time working on cars to waiting on customers= 2:1

Calculation:

We know, total working hours a day is = 8 hours.

Subtracting the hours of eating lunch and balancing books from total working hours,

  = 8−114

  =8−54

  =8×4−54=32−54=274hours

Therefore, He spends 274hours on working on cars and waiting on customers.

Also, Ratio of time working on cars to waiting on customers= 2:1

Let, 2:1= 2k:1k ( assuming k to be the common factor for the given ratio)

Therefore,

  2k+1k=274⇒3k=274⇒k=274×3⇒k=94=214hrs

Total hours spent waiting on customers, 1k = 1×214 = 214 hours

Thus, Howard spends 214 waiting on customers.

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Chapter 3, Problem 6CR
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Chapter 3, Problem 8CR

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 1OECh. 3.1 - Prob. 2OECh. 3.1 - Prob. 3OECh. 3.1 - Prob. 4OECh. 3.1 - Prob. 5OECh. 3.1 - Prob. 6OECh. 3.1 - Prob. 7OECh. 3.1 - Prob. 8OECh. 3.1 - Prob. 9OECh. 3.1 - Prob. 10OE
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