Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Concept explainers

Unitary Method
The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.
Speed, Time, and Distance
Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …
Profit and Loss
The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.
Units and Measurements
Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…
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Question
Book Icon
Chapter 3.6, Problem 11P
To determine

To find: Dimensions for each unrolled carpet with sketch.

Expert Solution & Answer
Check Mark

Answer to Problem 11P

The carpets are 9 ft. by 75 ft. and 15 ft. by 45 ft.

Explanation of Solution

Given information:

9 ft. wide carpet is 30 ft. longer than 15 ft. wide carpet.

Area for both rolls is same.

Let

The length of the 15 ft. wide carpet be x .

Then

The length of 9 ft. wide carpet be x + 30.

Since both rolls have same area.

Thus,

  9(x+30)=15x

That becomes

  9x+270=15x

Subtract 9x from both sides:

  270=6x

Divide both sides by 6:

  x=2706=45

Thus,

The length of 15ft. wide carpet is 45 ft.

We have

The length of 9ft. wide carpet is 30ft. longer than 15ft. wide carpet

Then

  x+30=45+30=75

The length of 9ft. wide carpet is 75ft.

Sketch for unrolled carpets is shown as:

  Algebra: Structure And Method, Book 1, Chapter 3.6, Problem 11P

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Chapter 3.6, Problem 10P
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Chapter 3.6, Problem 12P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 1OECh. 3.1 - Prob. 2OECh. 3.1 - Prob. 3OECh. 3.1 - Prob. 4OECh. 3.1 - Prob. 5OECh. 3.1 - Prob. 6OECh. 3.1 - Prob. 7OECh. 3.1 - Prob. 8OECh. 3.1 - Prob. 9OECh. 3.1 - Prob. 10OE
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