Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Chapter 3, Problem 19CT

i.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  0=0+0

i.

Expert Solution
Check Mark

Explanation of Solution

First take 0=0 then by adding 0 on the right hand side, we get0=0+0

Hence the property used here is identity property of addition

ii.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  a.0=a.(0+0)

ii.

Expert Solution
Check Mark

Explanation of Solution

From above part (i) we0=0+0 , now multiplying both sides bya , we geta.0=a.(0+0)

here, by multiplyinga both sides we get this, so Multiplicative Property of equality is used

iii.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  a.0=a.0+a.0

iii.

Expert Solution
Check Mark

Explanation of Solution

From the above part (ii), we havea.0=a.(0+0) , Now on the right hand side distributinga over the addition, we geta.0=a.0+a.0

Hence here we use distributive property.

iv.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  a.0+a.0=a.0+0

iv.

Expert Solution
Check Mark

Explanation of Solution

We know thata.0=0

By using the property of part (i), we havea.0=a.0+0...(ii)

Adding both above equations, we have

  a.0+a.0=a.0+0

here we substituteda.0=a.0+0 , so we used substitute property

v.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  a.0=0

v.

Expert Solution
Check Mark

Explanation of Solution

From above part (iv) we havea.0+a.0=a.0+0 , Now subtractinga.0 both sides we get

  a.0=0 ,

Hence here subtraction property of equality is used

vi.

To determine

To explain: Write the missing reasons to justify the multiplicative property of zero.

  0.a=0

vi.

Expert Solution
Check Mark

Explanation of Solution

From above part we havea.0=0 , by interchanging the position of 0 anda , we get0.a=0 , so this impliesa.0=0.a , which is commutative property of multiplication

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 11OECh. 3.1 - Prob. 12OECh. 3.1 - Prob. 13OECh. 3.1 - Prob. 14OECh. 3.1 - Prob. 15OECh. 3.1 - Prob. 16OECh. 3.1 - Prob. 17OECh. 3.1 - Prob. 18OECh. 3.1 - Prob. 19OECh. 3.1 - Prob. 20OECh. 3.1 - Prob. 21OECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - 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Prob. 7PCh. 3.4 - Prob. 8PCh. 3.4 - Prob. 9PCh. 3.4 - Prob. 10PCh. 3.4 - Prob. 11PCh. 3.4 - Prob. 12PCh. 3.4 - Prob. 13PCh. 3.4 - Prob. 14PCh. 3.4 - Prob. 15PCh. 3.4 - Prob. 16PCh. 3.4 - Prob. 17PCh. 3.4 - Prob. 18PCh. 3.4 - Prob. 19PCh. 3.4 - Prob. 20PCh. 3.4 - Prob. 21PCh. 3.4 - Prob. 22PCh. 3.4 - Prob. 23PCh. 3.4 - Prob. 24PCh. 3.4 - Prob. 25PCh. 3.4 - Prob. 26PCh. 3.4 - Prob. 27PCh. 3.4 - Prob. 28PCh. 3.4 - Prob. 29PCh. 3.4 - Prob. 30PCh. 3.4 - Prob. 31PCh. 3.4 - Prob. 32PCh. 3.4 - Prob. 33PCh. 3.4 - Prob. 1MRECh. 3.4 - Prob. 2MRECh. 3.4 - Prob. 3MRECh. 3.4 - Prob. 4MRECh. 3.4 - Prob. 5MRECh. 3.4 - Prob. 6MRECh. 3.4 - Prob. 7MRECh. 3.4 - Prob. 8MRECh. 3.4 - Prob. 9MRECh. 3.4 - Prob. 10MRECh. 3.4 - Prob. 11MRECh. 3.4 - Prob. 12MRECh. 3.5 - Prob. 1OECh. 3.5 - Prob. 2OECh. 3.5 - Prob. 3OECh. 3.5 - Prob. 4OECh. 3.5 - Prob. 5OECh. 3.5 - Prob. 6OECh. 3.5 - Prob. 7OECh. 3.5 - Prob. 8OECh. 3.5 - Prob. 9OECh. 3.5 - Prob. 10OECh. 3.5 - Prob. 11OECh. 3.5 - Prob. 12OECh. 3.5 - Prob. 1WECh. 3.5 - 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Prob. 5PCh. 3.5 - Prob. 6PCh. 3.5 - Prob. 7PCh. 3.5 - Prob. 8PCh. 3.5 - Prob. 9PCh. 3.5 - Prob. 10PCh. 3.5 - Prob. 11PCh. 3.5 - Prob. 12PCh. 3.5 - Prob. 13PCh. 3.5 - Prob. 14PCh. 3.5 - Prob. 15PCh. 3.5 - Prob. 16PCh. 3.5 - Prob. 17PCh. 3.5 - Prob. 18PCh. 3.5 - Prob. 19PCh. 3.5 - Prob. 20PCh. 3.5 - Prob. 1MRECh. 3.5 - Prob. 2MRECh. 3.5 - Prob. 3MRECh. 3.5 - Prob. 4MRECh. 3.5 - Prob. 5MRECh. 3.5 - Prob. 6MRECh. 3.5 - Prob. 7MRECh. 3.5 - Prob. 8MRECh. 3.5 - Prob. 9MRECh. 3.5 - Prob. 10MRECh. 3.5 - Prob. 11MRECh. 3.5 - Prob. 12MRECh. 3.5 - Prob. 1CECh. 3.5 - Prob. 2CECh. 3.5 - Prob. 3CECh. 3.5 - Prob. 4CECh. 3.5 - Prob. 5CECh. 3.5 - Prob. 6CECh. 3.5 - Prob. 1STCh. 3.5 - Prob. 2STCh. 3.5 - Prob. 3STCh. 3.5 - Prob. 4STCh. 3.6 - Prob. 1OECh. 3.6 - Prob. 2OECh. 3.6 - Prob. 3OECh. 3.6 - Prob. 1PCh. 3.6 - Prob. 2PCh. 3.6 - Prob. 3PCh. 3.6 - Prob. 4PCh. 3.6 - Prob. 5PCh. 3.6 - Prob. 6PCh. 3.6 - Prob. 7PCh. 3.6 - Prob. 8PCh. 3.6 - Prob. 9PCh. 3.6 - Prob. 10PCh. 3.6 - Prob. 11PCh. 3.6 - Prob. 12PCh. 3.6 - 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