Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Question

Chapter 3.4, Problem 29P

To determine

To solve: for the number of bottles capped by each of the given machines in one day.

Expert Solution & Answer

Answer to Problem 29P

The number of bottles capped by Machine A is =15800

The number of bottles capped by Machine B is =7900

The number of bottles capped by Machine C is =16300

Explanation of Solution

Given Information: There are three machines A, B and C which caps bottles in a day such that,

(1) The number of bottles capped by A is twice that of B. and Machine C caps 500 bottles more than that done by A.

(2) The total bottles capped by the three machines together is 40,000

The given statements express the relation between the number of bottles capped by three machines in a day.

Let the number of bottles capped by Machine A be x .

1. The first statement gives the number of bottles capped by B and C in terms of Machine A as 12x and (x+500) respectively.

2. The second statement gives the total number of bottles capped by the three machines together in a day as,

x+12x+(x+500)=40,000

Solving the equation gives the number of bottles capped by Machine A as,

2.5x+500=40,0002.5x=39500x=395002.5=15800

Now, the number of bottles capped by Machine B is given by,

12x=12×15800=7900

And, the bottles capped by Machine C is given by,

(x+500)=15800+500=16300

Chapter 3.4, Problem 28P

Chapter 3.4, Problem 30P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

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