Algebra: Structure And Method, Book 1

(REV)00 Edition

ISBN: 9780395977224

Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher: McDougal Littell

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Concept explainers

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.

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Question

Chapter 3.5, Problem 4P

To determine

To find: the value of number described

Expert Solution & Answer

Answer to Problem 4P

The value of the number described is 17

Explanation of Solution

Given information: “A number that is 68 greater than three times its opposite”

Concept Involved:

Assign variable for the unknown that we need to find.

Use the keywords in the statement to rewrite the statement to meaningful math equation.

“is” means =

“greater than” means +

“there times” means 3×

Solve the equation by getting the variable in one side of the equation and undoing whatever is done to it by performing reverse operation.

Calculation:

Let ‘ x’ be the number that we are trying to find. Rewrite the sentence by replacing the number with x .

x is 68 greater than 3 times the opposite of x .

Replace the keywords to get an equation representing the sentence given

x=68+−3x

In the process of getting x in one side of the equation add 3x on both sides

x+3x=68+−3x+3x

Combine like terms on both sides

4x=68

Divide by 4 on both sides of the equation

4x4=684

Simplify fraction on both sides of the equation

x=17

Conclusion:

A number that is 68 greater than three times its opposite is 17

Chapter 3.5, Problem 3P

Chapter 3.5, Problem 5P

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 1OE Ch. 3.1 - Prob. 2OE Ch. 3.1 - Prob. 3OE Ch. 3.1 - Prob. 4OE Ch. 3.1 - Prob. 5OE Ch. 3.1 - Prob. 6OE Ch. 3.1 - Prob. 7OE Ch. 3.1 - Prob. 8OE Ch. 3.1 - Prob. 9OE Ch. 3.1 - Prob. 10OE

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Prob. 6MRE Ch. 3.3 - Prob. 7MRE Ch. 3.3 - Prob. 8MRE Ch. 3.3 - Prob. 9MRE Ch. 3.3 - Prob. 10MRE Ch. 3.3 - Prob. 11MRE Ch. 3.3 - Prob. 12MRE Ch. 3.3 - Prob. 1E Ch. 3.3 - Prob. 2E Ch. 3.3 - Prob. 3E Ch. 3.4 - Prob. 1P Ch. 3.4 - Prob. 2P Ch. 3.4 - Prob. 3P Ch. 3.4 - Prob. 4P Ch. 3.4 - Prob. 5P Ch. 3.4 - Prob. 6P Ch. 3.4 - Prob. 7P Ch. 3.4 - Prob. 8P Ch. 3.4 - Prob. 9P Ch. 3.4 - Prob. 10P Ch. 3.4 - Prob. 11P Ch. 3.4 - Prob. 12P Ch. 3.4 - Prob. 13P Ch. 3.4 - Prob. 14P Ch. 3.4 - Prob. 15P Ch. 3.4 - Prob. 16P Ch. 3.4 - Prob. 17P Ch. 3.4 - Prob. 18P Ch. 3.4 - Prob. 19P Ch. 3.4 - Prob. 20P Ch. 3.4 - Prob. 21P Ch. 3.4 - Prob. 22P Ch. 3.4 - Prob. 23P Ch. 3.4 - Prob. 24P Ch. 3.4 - Prob. 25P Ch. 3.4 - Prob. 26P Ch. 3.4 - Prob. 27P Ch. 3.4 - Prob. 28P Ch. 3.4 - Prob. 29P Ch. 3.4 - Prob. 30P Ch. 3.4 - Prob. 31P Ch. 3.4 - Prob. 32P Ch. 3.4 - Prob. 33P Ch. 3.4 - Prob. 1MRE Ch. 3.4 - Prob. 2MRE Ch. 3.4 - Prob. 3MRE Ch. 3.4 - Prob. 4MRE Ch. 3.4 - Prob. 5MRE Ch. 3.4 - Prob. 6MRE Ch. 3.4 - Prob. 7MRE Ch. 3.4 - 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