Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00 Edition
ISBN: 9780395977224
Author: Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher: McDougal Littell
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Chapter 3.5, Problem 12P
To determine

To find: the numbers based on the given description

Expert Solution & Answer
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Answer to Problem 12P

The smaller number is 17 and the larger number is 26 .

Explanation of Solution

Given information: “The difference of two numbers is 9”, “Five times the smaller is 7 more than three times the larger”

Concept Involved:

Assign variable for the unknown that we need to find.

Use the keywords in the statement to rewrite the statement to meaningful math equation.

“is” means =

“more than” means +

“Difference” means -

“times” means ×

Solve the equation by getting the variable in one side of the equation and undoing whatever is done to it by performing reverse operation.

Calculation: Assign variable for the unknown that we need to find

Let x represents smaller number

Since the difference of two numbers is 9, the expression that represents the larger number is x more than 9.

  x+9

Rewrite the statement “Five times the smaller is 7 more than three times the larger” in terms of x

5 times x is 7 more than 3 times x+9

Use the keywords to write the statement “Five times the smaller is 7 more than three times the larger” as an equation

  5x=7+3(x+9)

Distribute 5 in right side of the equation

  5x=7+3x+27

In the process of getting x in one side of the equation subtract 3x on both sides

  5x3x=34+3x3x

Combine like terms on both sides

  2x=34

Divide 2 on both sides of the equation

  2x2=342

Simplify fraction on both sides of the equation

  x=17

Substitute 17 for x in the expression x+9 to identify the larger number

  17+9=26

Conclusion:

The smaller number is 17 and the larger number is 26 .

Chapter 3 Solutions

Algebra: Structure And Method, Book 1

Ch. 3.1 - Prob. 11OECh. 3.1 - Prob. 12OECh. 3.1 - Prob. 13OECh. 3.1 - Prob. 14OECh. 3.1 - Prob. 15OECh. 3.1 - Prob. 16OECh. 3.1 - Prob. 17OECh. 3.1 - Prob. 18OECh. 3.1 - Prob. 19OECh. 3.1 - Prob. 20OECh. 3.1 - Prob. 21OECh. 3.1 - Prob. 1WECh. 3.1 - Prob. 2WECh. 3.1 - Prob. 3WECh. 3.1 - Prob. 4WECh. 3.1 - Prob. 5WECh. 3.1 - Prob. 6WECh. 3.1 - Prob. 7WECh. 3.1 - Prob. 8WECh. 3.1 - Prob. 9WECh. 3.1 - Prob. 10WECh. 3.1 - Prob. 11WECh. 3.1 - Prob. 12WECh. 3.1 - Prob. 13WECh. 3.1 - Prob. 14WECh. 3.1 - Prob. 15WECh. 3.1 - Prob. 16WECh. 3.1 - Prob. 17WECh. 3.1 - Prob. 18WECh. 3.1 - Prob. 19WECh. 3.1 - Prob. 20WECh. 3.1 - Prob. 21WECh. 3.1 - Prob. 22WECh. 3.1 - Prob. 23WECh. 3.1 - Prob. 24WECh. 3.1 - Prob. 25WECh. 3.1 - Prob. 26WECh. 3.1 - Prob. 27WECh. 3.1 - Prob. 28WECh. 3.1 - Prob. 29WECh. 3.1 - Prob. 30WECh. 3.1 - Prob. 31WECh. 3.1 - Prob. 32WECh. 3.1 - Prob. 33WECh. 3.1 - Prob. 34WECh. 3.1 - Prob. 35WECh. 3.1 - Prob. 36WECh. 3.1 - Prob. 37WECh. 3.1 - Prob. 38WECh. 3.1 - Prob. 39WECh. 3.1 - 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