Chapter 35, Problem 24A

Calculate the current in a 48-V battery that powers a pair of $30\text{-}\Omega$ resistors connected in parallel.

To determine

The current through the battery.

Answer to Problem 24A

The current through the battery is $3.2\text{A}$ .

Explanation of Solution

Given info:

Number of resistance in the parallel, $n=2$

Voltage across the battery, $V=48\text{V}$

Resistance of the resistor, $R=30\Omega$

Formula used:

The expression to calculate the equivalent resistance of the battery is,

$R_p=\frac{R}{n}$

The expression to calculate the current in the battery is,

$I=\frac{V}{R_p}$

Calculation:

Substitute the given values in the above expression.

$\begin{array}{c}{R}_s=\frac{30\Omega }{2}\\ =15\Omega \end{array}$

Substitute the given values in the above expression.

$\begin{array}{c}I=\frac{48\text{V}}{15\Omega }\\ =3.2\text{A}\end{array}$

Conclusion:

The current through the battery is $3.2\text{A}$ .