Chapter 35, Problem 49A

A lightbulb connected to a 3.0-V battery draws 1.2 A of current. Calculate the resistance of the bulb.

To determine

The resistance of the bulb.

Answer to Problem 49A

The resistance of the bulb is $2.5\Omega$ .

Explanation of Solution

Given info:

Voltage of the battery, $V=3\text{V}$

Current drawn by lightbulb, $I=1.2\text{A}$

Formula used:

The expression to calculate the resistance of the bulb is,

  $R=\frac{V}{I}$

Calculation:

Substitute given values in the above expression.

  $\begin{array}{c}R=\frac{3\text{V}}{1.2\text{A}}\\ =2.5\Omega \end{array}$

Conclusion:

The resistance of the bulb is $2.5\Omega$ .