Chapter 3.3, Problem 54LC

Interpretation Introduction

Interpretation : The mass of gasoline is to be calculated.

Concept Introduction : Mass is a measure used to quantify an object in comparison to that standard mass of 1 kilogram.

  $\text{Mass}\text{=}\text{Density}\times \text{Volume}$

Answer to Problem 54LC

The mass of gasoline is $9.52\times {10}^3\text{g}$ .

Explanation of Solution

Given information :

The volume is $14.0\text{L}$ .

The density of gasoline is $0.680{\text{g/cm}}^3$ .

Mass is a measure used to quantify an object in comparison to that standard mass of 1 kilogram.

  $\text{Mass}\text{=}\text{Density}\times \text{Volume}$

To calculate the mass, substitute the values in the above formula.

  $\begin{array}{c}\text{Mass}\text{=}\text{Density}\times \text{Volume}\\ \text{=}0.680\text{g}\text{/}\cancel{{\text{cm}}^3}\times 14\cancel{\text{L}}\times \frac{{10}^3\cancel{{\text{cm}}^3}}{1\cancel{\text{L}}}\\ =9.52\times {10}^3\text{g}\end{array}$

Conclusion

The mass of gasoline is $9.52\times {10}^3\text{g}$ .