Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Question

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Answer 1

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

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2. Signed Integers Unsigned binary numbers work for natural numbers, but many calculations use negative numbers as well. To deal with this, a number of different methods have been used to represent signed numbers, but we will focus on two's complement, as it is the standard solution for representing signed integers. 2.1 Two's complement • Most significant bit has a negative value, all others are positive. So, the value of an n-digit -2 two's complement number can be written as: Σ2 2¹ di 2n-1 dn • Otherwise exactly the same as unsigned integers. i=0 - • A neat trick for flipping the sign of a two's complement number: flip all the bits (0 becomes 1, or 1 becomes 0) and then add 1 to the least significant bit. • Addition is exactly the same as with an unsigned number. 2.2 Exercises For questions 1-3, answer each one for the case of a two's complement number and an unsigned number, indicating if it cannot be answered with a specific representation. 1. (15 pts) What is the largest integer…

Answer 2

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 8

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 9

Chapter 3.10, Problem 3.46PP

A.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 10

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 11

B.

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Answer 12

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Answer 13

C.

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Answer 14

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Answer 15

D.

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Answer 16

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 17

E.

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Check out a sample textbook solution

See solution

Answer 21

Ch. 3.4 - Prob. 3.1PP Ch. 3.4 - Prob. 3.2PP Ch. 3.4 - Prob. 3.3PP Ch. 3.4 - Prob. 3.4PP Ch. 3.4 - Prob. 3.5PP Ch. 3.5 - Prob. 3.6PP Ch. 3.5 - Prob. 3.7PP Ch. 3.5 - Prob. 3.8PP Ch. 3.5 - Prob. 3.9PP Ch. 3.5 - Prob. 3.10PP

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Solution Summary: The author explains that each box in table represents 8 bytes. The hexadecimal values are stored inside table.

Explanation of Solution

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Explanation of Solution

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Explanation of Solution

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Explanation of Solution

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Explanation of Solution

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Want to see the full answer?

Chapter 3 Solutions

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 76 01 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Solution Summary: The author explains that each box in table represents 8 bytes. The hexadecimal values are stored inside table.

Explanation of Solution

Stack after line 3: The stack details are shown below: 00 00 00 00 00 40 00 7601 23 45 67 89 AB CD EF Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Explanation of Solution

Stack after line 5: The stack details are shown below: 00 00 00 00 00 40 00 3433 32 31 30 39 38 37 3635 34 33 32 31 30 39 3837 36 35 34 33 32 31 30 Return address Saved %rbx buf = %rsp Explanation: Each box in table represents 8 bytes...

Explanation of Solution

Address of program return: The program attempts to return to address “0x040034”. The low-order 2 bytes ...

Explanation of Solution

Registers with corrupted values: The register “%rbx” has saved value that is set to “0x3332313039383736”...

Explanation of Solution

Error in get_line code: The call to “malloc” method has argument “strlen(buf)”. The argument should be “strlen(buf)+1” instead of “strlen(buf)”...

Want to see the full answer?

Chapter 3 Solutions

Stack after line 3:

The stack details are shown below:

00 00 00 00 00 40 00 76
01 23 45 67 89 AB CD EF

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Stack after line 5:

The stack details are shown below:

00 00 00 00 00 40 00 34
33 32 31 30 39 38 37 36
35 34 33 32 31 30 39 38
37 36 35 34 33 32 31 30

Return address

Saved %rbx

buf = %rsp

Explanation:

Each box in table represents 8 bytes...

Address of program return:

The program attempts to return to address “0x040034”.

The low-order 2 bytes ...

Registers with corrupted values:

The register “%rbx” has saved value that is set to “0x3332313039383736”...

Error in get_line code:

The call to “malloc” method has argument “strlen(buf)”.

The argument should be “strlen(buf)+1” instead of “strlen(buf)”...