Chapter 3.11, Problem 3.55PP

Explanation of Solution

Given code:

double cel2fahr(double temp)

temp in %xmm0

cel2fahr:

vmulsd .LC2(%rip), %xmm0, %xmm0

vaddsd .LC3(%rip), %xmm0, %xmm0

ret

.LC2:

.long 3435973837

.long 1073532108

.LC3:

.long 0

.long 1077936128

Explanation:

• The given code saves two numbers in both labels “.LC2” and “.LC3”.
• The instruction “vmulsd .LC2(%rip), %xmm0, %xmm0” multiplies the number by 1.8.
• The instruction “vaddsd .LC3(%rip), %xmm0, %xmm0” adds 32 to the result.
• The instruction “ret” denotes a return statement.

Encode numbers declared at label ...