Computer Systems: A Programmer's Perspective (3rd Edition)
3rd Edition
ISBN: 9780134092669
Author: Bryant, Randal E. Bryant, David R. O'Hallaron, David R., Randal E.; O'Hallaron, Bryant/O'hallaron
Publisher: PEARSON
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Question
Chapter 3.6, Problem 3.15PP
a.
Program Plan Intro
Jump Instruction:
- The “jump” instruction causes execution to switch to an entirely new position in program.
- The “label” indicates jump destinations in assembly code.
- The “je” instruction denotes “jump if equal” or “jump if zero”.
- The comparison operation is performed.
- If result of comparison is either equal or zero, then jump operation takes place.
- The “ja” instruction denotes “jump if above”.
- The comparison operation is performed.
- If result of comparison is greater, then jump operation takes place.
- The “pop” instruction resumes execution of jump instruction.
- The “jmpq” instruction jumps to given address. It denotes a direct jump.
b.
Program Plan Intro
Jump Instruction:
- The “jump” instruction causes execution to switch to an entirely new position in program.
- The “label” indicates jump destinations in assembly code.
- The “je” instruction denotes “jump if equal” or “jump if zero”.
- The comparison operation is performed.
- If result of comparison is either equal or zero, then jump operation takes place.
- The “ja” instruction denotes “jump if above”.
- The comparison operation is performed.
- If result of comparison is greater, then jump operation takes place.
- The “pop” instruction resumes execution of jump instruction.
- The “jmpq” instruction jumps to given address. It denotes a direct jump.
c.
Program Plan Intro
Jump Instruction:
- The “jump” instruction causes execution to switch to an entirely new position in program.
- The “label” indicates jump destinations in assembly code.
- The “je” instruction denotes “jump if equal” or “jump if zero”.
- The comparison operation is performed.
- If result of comparison is either equal or zero, then jump operation takes place.
- The “ja” instruction denotes “jump if above”.
- The comparison operation is performed.
- If result of comparison is greater, then jump operation takes place.
- The “pop” instruction resumes execution of jump instruction.
- The “jmpq” instruction jumps to given address. It denotes a direct jump.
d.
Program Plan Intro
Jump Instruction:
- The “jump” instruction causes execution to switch to an entirely new position in program.
- The “label” indicates jump destinations in assembly code.
- The “je” instruction denotes “jump if equal” or “jump if zero”.
- The comparison operation is performed.
- If result of comparison is either equal or zero, then jump operation takes place.
- The “ja” instruction denotes “jump if above”.
- The comparison operation is performed.
- If result of comparison is greater, then jump operation takes place.
- The “pop” instruction resumes execution of jump instruction.
- The “jmpq” instruction jumps to given address. It denotes a direct jump.
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
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We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
using r language
Chapter 3 Solutions
Computer Systems: A Programmer's Perspective (3rd Edition)
Ch. 3.4 - Prob. 3.1PPCh. 3.4 - Prob. 3.2PPCh. 3.4 - Prob. 3.3PPCh. 3.4 - Prob. 3.4PPCh. 3.4 - Prob. 3.5PPCh. 3.5 - Prob. 3.6PPCh. 3.5 - Prob. 3.7PPCh. 3.5 - Prob. 3.8PPCh. 3.5 - Prob. 3.9PPCh. 3.5 - Prob. 3.10PP
Ch. 3.5 - Prob. 3.11PPCh. 3.5 - Prob. 3.12PPCh. 3.6 - Prob. 3.13PPCh. 3.6 - Prob. 3.14PPCh. 3.6 - Prob. 3.15PPCh. 3.6 - Prob. 3.16PPCh. 3.6 - Practice Problem 3.17 (solution page 331) An...Ch. 3.6 - Practice Problem 3.18 (solution page 332) Starting...Ch. 3.6 - Prob. 3.19PPCh. 3.6 - Prob. 3.20PPCh. 3.6 - Prob. 3.21PPCh. 3.6 - Prob. 3.22PPCh. 3.6 - Prob. 3.23PPCh. 3.6 - Practice Problem 3.24 (solution page 335) For C...Ch. 3.6 - Prob. 3.25PPCh. 3.6 - Prob. 3.26PPCh. 3.6 - Practice Problem 3.27 (solution page 336) Write...Ch. 3.6 - Prob. 3.28PPCh. 3.6 - Prob. 3.29PPCh. 3.6 - Practice Problem 3.30 (solution page 338) In the C...Ch. 3.6 - Prob. 3.31PPCh. 3.7 - Prob. 3.32PPCh. 3.7 - Prob. 3.33PPCh. 3.7 - Prob. 3.34PPCh. 3.7 - Prob. 3.35PPCh. 3.8 - Prob. 3.36PPCh. 3.8 - Prob. 3.37PPCh. 3.8 - Prob. 3.38PPCh. 3.8 - Prob. 3.39PPCh. 3.8 - Prob. 3.40PPCh. 3.9 - Prob. 3.41PPCh. 3.9 - Prob. 3.42PPCh. 3.9 - Practice Problem 3.43 (solution page 344) Suppose...Ch. 3.9 - Prob. 3.44PPCh. 3.9 - Prob. 3.45PPCh. 3.10 - Prob. 3.46PPCh. 3.10 - Prob. 3.47PPCh. 3.10 - Prob. 3.48PPCh. 3.10 - Prob. 3.49PPCh. 3.11 - Practice Problem 3.50 (solution page 347) For the...Ch. 3.11 - Prob. 3.51PPCh. 3.11 - Prob. 3.52PPCh. 3.11 - Practice Problem 3.52 (solution page 348) For the...Ch. 3.11 - Practice Problem 3.54 (solution page 349) Function...Ch. 3.11 - Prob. 3.55PPCh. 3.11 - Prob. 3.56PPCh. 3.11 - Practice Problem 3.57 (solution page 350) Function...Ch. 3 - For a function with prototype long decoda2(long x,...Ch. 3 - The following code computes the 128-bit product of...Ch. 3 - Prob. 3.60HWCh. 3 - In Section 3.6.6, we examined the following code...Ch. 3 - The code that follows shows an example of...Ch. 3 - This problem will give you a chance to reverb...Ch. 3 - Consider the following source code, where R, S,...Ch. 3 - The following code transposes the elements of an M...Ch. 3 - Prob. 3.66HWCh. 3 - For this exercise, we will examine the code...Ch. 3 - Prob. 3.68HWCh. 3 - Prob. 3.69HWCh. 3 - Consider the following union declaration: This...Ch. 3 - Prob. 3.71HWCh. 3 - Prob. 3.72HWCh. 3 - Prob. 3.73HWCh. 3 - Prob. 3.74HWCh. 3 - Prob. 3.75HW
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