Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
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ISBN: 9781260170405
Author: SMITH
Publisher: MCG
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Chapter 31, Problem 31.29P
An isoprene unit can be thought of as having a head and a tail. The “head” of the isoprene unit is located at the end of the chain nearest the branch point, and the “tail” is located at the end of the carbon chain farthest from the branch point. Most isoprene units are connected together in a “head-to-tail” fashion, as illustrated. For both lycopene (Problem 31.26), and squalene (Figure 31.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
These two isoprene units are
connected in head-tail fashion.
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An isoprene unit can be thought of as having a head and a tail. The "head" of the isoprene unit is located at the end of the chain
nearest the branch point, and the "tail" is located at the end of the carbon chain farthest from the branch point. Most isoprene
units are connected together in a "head-to-tail" fashion, as illustrated. For both lycopene (Problem 30.28), and squalene (Figure
30.9), decide which isoprene units are connected in a head-to-tail fashion and which are not.
head tail
tail head
These two isoprene units are
connected in a head-to-tail fashion.
Show the structure of the furfural products/derivatives of the given compounds which were subjected to Seliwanoff's Test.
compounds: sucrose, fructose, and glucose
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a(12)
glucose
a(14)
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Match the words in the left column to the appropriate blanks in the sentences on the right.
glucose
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fructose
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Both are linear polysaccharides composed entirely of
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2
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In amylose, the glycosidic
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Chapter 31 Solutions
Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
Ch. 31 - Problem 31.1
One component of jojoba oil is a wax...Ch. 31 - Problem 31.2
How would you expect the melting...Ch. 31 - Problem 31.3
Draw the products formed when...Ch. 31 - Problem 31.4
The main fatty acid component of the...Ch. 31 - Prob. 31.5PCh. 31 - Problem 31.6
Draw the structure of a lecithin...Ch. 31 - Prob. 31.7PCh. 31 - Problem 31.8
Why are phospholipids, but not...Ch. 31 - Problem 31.9
Explain why regularly ingesting a...Ch. 31 - Problem 31.10
Locate the isoprene units in each...
Ch. 31 - Problem 31.11
Locate the isoprene units in...Ch. 31 - Problem 31.12
Write a stepwise mechanism for the...Ch. 31 - Prob. 31.13PCh. 31 - Prob. 31.14PCh. 31 - Prob. 31.15PCh. 31 - Prob. 31.16PCh. 31 - 31.17 Locate the isoprene units in each...Ch. 31 - Prob. 31.18PCh. 31 - Prob. 31.19PCh. 31 - Prob. 31.20PCh. 31 - Prob. 31.21PCh. 31 - 31.22 What is the structure of an optically...Ch. 31 - Prob. 31.23PCh. 31 - 31.24 Draw the structure of the following...Ch. 31 - Prob. 31.25PCh. 31 - Locate the isoprene units in each compound. a. e....Ch. 31 - 31.27 Classify each terpene and terpenoid in...Ch. 31 - 31.38 Draw the products formed when cholesterol is...Ch. 31 - 31.29 An isoprene unit can be thought of as having...Ch. 31 - 31.30 Draw a stepwise mechanism for the conversion...Ch. 31 - Prob. 31.31PCh. 31 - Prob. 31.32PCh. 31 - Draw three-dimensional structures f or each...Ch. 31 - Prob. 31.34PCh. 31 - Prob. 31.35PCh. 31 - Prob. 31.36PCh. 31 - Prob. 31.37PCh. 31 - 31.38 Draw the products formed when cholesterol is...Ch. 31 - 31.39 Draw a stepwise mechanism for the following...Ch. 31 - 31.40 Draw a stepwise mechanism for the following...Ch. 31 - Prob. 31.41P
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- Cellulose is water insoluble, despite its many OH groups. Considering its three-dimensional structure, why do you think this is so?arrow_forward10) All six molecules shown below are examples of...Highlight/bold your answer. See pp. 71-73 of your text for help. Nucleic Acids or Carbohydrates or Lipids or Proteins (1) (2) (3) (4) (5) (6) HO CH,OH H-C-CH HO-C-H H-C-CH H-C-CH CH,OH OH H-C-OH C=0 H-C-OH HO-C-H H-C-CH H-C-OH CH,OH H-C-OH H--CH -OH a. Based on the molecules you see above, list at least two structural characteristics that are common to all carbohydrates. b. Based on the molecules you see above, list at least three ways that carbohydrates can differ from one another.arrow_forwardIn general, the starch hydrolysis reaction can be written as (C6H10O5)n + H2O -> (C6H10O5)n-1 + C6H12O6, where one glucose is produced for every water added. Because of the addition of water, the mass of the glucose monomer increases during hydrolysis from approximately 162g/mol in the starch polymer to 180g/mol as free sugar. The glucose, in turn is converted to ethanol by the yeast, Saccharomyces cerevisiae, according to the reaction, C6H12O6 -> 2 CO2 + 2 C2H5OH. The starch in 25kg (~1 bushel) of corn is hydrolyzed and in the process 1.8kg of water (H2O) is consumed. How many moles of glucose (C6H12O6) would you expect to be produced? If the glucose from the above hydrolysis is fermented, how many moles of ethanol (C2H5OH) would result? How many grams?arrow_forward
- 43. Specify expressions specific to panaxosides. I. taken from ginseng II. there are glucose and arabinose monosaccharides in this compound III. taken from Japanese angelica-tree IV. tetratcyclic triterpen saponins V. spirostanol type glycoside VI. dimer structure VII. biglycosides VIII. dammaran group IX. differ for number of hydroxyl groups X. furostanol type glycoside A) II; VI; VII; IX; X B) III; V; VIII C) I; IV; VIII; IX D) I; VIII; IX E) I; III; V; VII; VIII; Xarrow_forwardShow the structure of the furfural products/derivatives of the given compounds which were subjected to Molisch Test. compounds: starch, sucrose, and glucosearrow_forwardMonosaccharides are cyclic hemiacetals that can react with alcohols to form acetals. The bond between the anomeric carbon atom of the monosaccharide and the oxygen atom of the -OR group is called a glycosidic bond. The name of the linkage contains the designation alpha (a) or beta (B) (from the anomeric carbon in the glycosidic bond) and the carbon numbers for the carbons from the two sugars. For this example, the linkage is an a-1,4 glycosidic bond. Н НО HO اب تاب است H OH H OH -OH Н Н OH H + OH HO a anomer CH₂OH H Н H О OH H2C OH Н H Classify the glycosidic linkage in the disaccharide. Н OH Н H OH OH OH - HO Н H HO OH OH Н CH₂OH H -OH H OH он H H -OH Н OH an a glycosidic bond Н OH + H2O о о о о В-1,6 a-1,6 a-1,1 B-1,5 I DON'T KNOW YET submitarrow_forward
- Which statement about saccharides is correct? (A). Alpha anomers are more common than beta anoomers. (B). Two monosaccharides can form a disaccharide and oxygen. (C). Polysaccharides with alpha or beta glycosidic linkages have the different properties. (D). Disaccharides can be cyclic or acyclic.arrow_forwardExplain why lactose and maltose differs from sucrose in its chemical activity with Fehling’s, Benedict’s and using Seliwanoff’s reagents?arrow_forwardDraw out the structure for lycopene:- Mark each isoprene unit- Where is lycopene found in nature and what health benefits does it provide?arrow_forward
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