
Concept explainers
(a)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(a)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is given below.
The number of oxygen atom on reactant side is three whereas on product side is five.
The number of hydrogen atom on reactant side is two whereas on product side is three.
The number of potassium atom on reactant side and product side is one.
In order to balance the equation, add coefficient
The number of hydrogen atom on reactant side is two whereas on product side is four.
The number of potassium atom on reactant side and product side is two.
The number of oxygen atom on reactant side is five whereas on product side is six.
In order to balance the equation, add coefficient
Thus, all the atoms of potassium, hydrogen and oxygen are balanced on reactant and product side.
Therefore, the balanced chemical equation is
(b)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(b)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is shown below.
The number of oxygen atom on reactant side is six whereas on product side is ten.
The number of hydrogen atom on reactant side is one whereas on product side is two.
The number of iron atom on reactant side is two and product side is one.
The number of nitrogen atom on reactant side is one and product side is three.
To balance the equation, add coefficient
The equation would become as follows.
The number of oxygen atom on reactant side is twenty-one whereas on product side is nineteen.
The number of hydrogen atom on reactant side is six whereas on product side is two.
The number of iron atom on reactant side and product side is two.
The number of nitrogen atom on reactant side and product side is six.
In order to balance the equation, add coefficient three in front of
Thus, all the atoms of iron, nitrogen, hydrogen, and oxygen are balanced on reactant and product side.
Therefore, the balanced chemical equation is
(c)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(c)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is shown below.
The number of oxygen atom on reactant and product side is two.
The number of hydrogen atom on reactant side is three whereas on product side is two.
The number of nitrogen atom on reactant and product side is one.
To balance the equation, add coefficient
The number of oxygen atom on reactant side is two whereas on product side is five.
The number of hydrogen atom on reactant side is twelve whereas on product side is two.
The number of nitrogen atom on reactant side and product side is four.
To balance the equation, add coefficient
The equation would become as follows.
Thus, all the atoms of nitrogen, hydrogen, and oxygen are balanced on reactant and product side.
Therefore, the balanced chemical equation is
(d)
Interpretation: The balanced form of chemical equation,
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(d)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is shown below.
The number of oxygen atom on reactant side is one whereas on product side is four.
The number of hydrogen atom on reactant side is two whereas on product side is four.
The number of phosphorus atom on reactant side and product side is one.
The number of chlorine atom on reactant side is five and product side is one.
To balance the equation, add coefficient
The equation would become as follows.
Thus, all the atoms of phosphorous, oxygen, hydrogen and chlorine are balanced.
Therefore, the balanced chemical equation is
(e)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(e)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is given below.
The number of oxygen atom on reactant side is one whereas on product side is two.
The number of carbon atom on reactant side is one whereas on product side is three.
The number of calcium atom on reactant side and product side is one.
To balance the equation, add coefficient
The equation would become as follows.
The number of oxygen atom on reactant and product side is two.
The number of carbon atom on reactant side is one whereas on product side is five.
The number of calcium atom on reactant side and product side is two.
To balance the equation, add coefficient
Thus, all the atoms of calcium, oxygen and carbon on reactant and product side are balanced.
Therefore, the balanced chemical equation is
(f)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(f)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is shown below.
The number of oxygen atom on reactant side is two whereas on product side is five.
The number of sulfur atom on reactant side is two whereas on product side is one.
The number of molybdenum atom on reactant side and product side is one.
To balance the equation, add coefficient
The equation would become as follows.
The number of oxygen atom on reactant side is two and product side is eight.
The number of sulfur atom on reactant side is four whereas on product side is one.
The number of molybdenum atom on reactant side and product side is two.
To balance the equation, add coefficient
Thus, all the atoms of molybdenum, sulfur and oxygen on reactant and product side are balanced.
Therefore, the balanced chemical equation is.
(g)
Interpretation: The balanced form of chemical equation
Concept introduction: In any balanced chemical equation, the number of all the atoms or elements exists on the reactant side equal to the number of all the atoms or elements present on the product side. Every measurement is dependent on the balanced equation. This is further used in determining the number of moles of reacting species, which is the key step in every calculation.
(g)

Answer to Problem 70E
The balanced form of chemical equation is
Explanation of Solution
The given chemical equation is shown below.
The number of oxygen atom on reactant and product side is six.
The number of hydrogen atom on reactant and product side is two.
The number of iron atom on reactant and product side is one.
The number of carbon atom on reactant on reactant and product side is two.
Thus, the number of
Therefore, the balanced chemical equation is
Want to see more full solutions like this?
Chapter 3 Solutions
Chemical Principles
- What is the IUPAC name of the following compound? CH₂CH₂ H CI H₂CH₂C H CH₂ Selected Answer: O (35,4R)-4 chloro-3-ethylpentane Correctarrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. I I I H Select to Add Arrows HCI, CH3CH2OHarrow_forward
- Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and the follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the intermediates and product of the following reaction or mechanistic step(s).arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and the product in this reaction or mechanistic step(s).arrow_forward
- Look at the following pairs of structures carefully to identify them as representing a) completely different compounds, b) compounds that are structural isomers of each other, c) compounds that are geometric isomers of each other, d) conformers of the same compound (part of structure rotated around a single bond) or e) the same structure.arrow_forwardGiven 10.0 g of NaOH, what volume of a 0.100 M solution of H2SO4 would be required to exactly react all the NaOH?arrow_forward3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forward
- 3.50 g of Li are combined with 3.50 g of N2. What is the maximum mass of Li3N that can be produced? 6 Li + N2 ---> 2 Li3Narrow_forwardConcentration Trial1 Concentration of iodide solution (mA) 255.8 Concentration of thiosulfate solution (mM) 47.0 Concentration of hydrogen peroxide solution (mM) 110.1 Temperature of iodide solution ('C) 25.0 Volume of iodide solution (1) used (mL) 10.0 Volume of thiosulfate solution (5:03) used (mL) Volume of DI water used (mL) Volume of hydrogen peroxide solution (H₂O₂) used (mL) 1.0 2.5 7.5 Time (s) 16.9 Dark blue Observations Initial concentration of iodide in reaction (mA) Initial concentration of thiosulfate in reaction (mA) Initial concentration of hydrogen peroxide in reaction (mA) Initial Rate (mA's)arrow_forwardDraw the condensed or line-angle structure for an alkene with the formula C5H10. Note: Avoid selecting cis-/trans- isomers in this exercise. Draw two additional condensed or line-angle structures for alkenes with the formula C5H10. Record the name of the isomers in Data Table 1. Repeat steps for 2 cyclic isomers of C5H10arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning





