ACHIEVE:INTRO TO GENETIC ANALYSIS 1TERM
12th Edition
ISBN: 9781319401399
Author: Griffiths
Publisher: MAC HIGHER
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Chapter 3, Problem 43.3P
Summary Introduction
To determine: The diagrammatic cross between the different
Introduction: Evolution is the change in the phenotypic or genotypic characters of the species as a whole with passing generations; this can take place due to several internal and external factors.
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What is the opening indicated by the pointer? (leaf x.s.)
stomate
guard cell
lenticel
intercellular space
none of these
Identify the indicated tissue? (stem x.s.)
parenchyma
collenchyma
sclerenchyma
○ xylem
○ phloem
none of these
Where did this structure originate from? (Salix branch root)
epidermis
cortex
endodermis
pericycle
vascular cylinder
Chapter 3 Solutions
ACHIEVE:INTRO TO GENETIC ANALYSIS 1TERM
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 43.1PCh. 3 - Prob. 43.2PCh. 3 - Prob. 43.3PCh. 3 - Prob. 43.4PCh. 3 - Prob. 43.5PCh. 3 - Prob. 43.6PCh. 3 - Prob. 43.7PCh. 3 - Prob. 43.8PCh. 3 - Prob. 43.9PCh. 3 - Prob. 43.10PCh. 3 - Prob. 43.11PCh. 3 - Prob. 43.12PCh. 3 - Prob. 43.13PCh. 3 - Prob. 43.14PCh. 3 - Prob. 43.15PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 70PCh. 3 - Prob. 1GSCh. 3 - Prob. 2GSCh. 3 - Prob. 3GS
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- Identify the indicated tissue. (Tilia stem x.s.) parenchyma collenchyma sclerenchyma xylem phloem none of thesearrow_forwardIdentify the indicated structure. (Cucurbita stem l.s.) pit lenticel stomate tendril none of thesearrow_forwardIdentify the specific cell? (Zebrina leaf peel) vessel element sieve element companion cell tracheid guard cell subsidiary cell none of thesearrow_forward
- What type of cells flank the opening on either side? (leaf x.s.) vessel elements sieve elements companion cells tracheids guard cells none of thesearrow_forwardWhat specific cell is indicated. (Cucurbita stem I.s.) vessel element sieve element O companion cell tracheid guard cell none of thesearrow_forwardWhat specific cell is indicated? (Aristolochia stem x.s.) vessel element sieve element ○ companion cell O O O O O tracheid O guard cell none of thesearrow_forward
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- You are studying the effect of directional selection on body height in three populations (graphs a, b, and c below). (a) What is the selection differential? Show your calculation. (2 pts) (b) Which population has the highest narrow sense heritability for height? Explain your answer. (2 pts) (c) If you examined the offspring in the next generation in each population, which population would have the highest mean height? Why? (2 pts) (a) Midoffspring height (average height of offspring) Short Short Short Short (c) Short (b) Short Tall Short Tall Short Short Tall Midparent height (average height of Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inchesarrow_forwardP You are studying a population of 100 flowers that has two alleles at a locus for flower color, blue (B) and green (G). There are 15 individuals with the BB genotype, 70 individuals with the BG genotype, and 15 individuals with the GG genotype. (a) What are the allele frequencies of B and G in the starting population? Show your calculations. (2 pts) (b) Is this population in Hardy-Weinberg equilibrium? Show your calculations. (3 pts) 12pt v Paragraph BIU UA AV & VT2V f CO Varrow_forwardIn a natural population of outbreeding plants, the variance of the total number of seeds per plant is 16. From the natural population, 20 plants are taken into the laboratory and developed into separate true-breeding lines by self- fertilization-with selection for high, low, or medium number of seeds-for 10 generations. The average variance in the tenth generation in each of the 20 sets is about equal and averages 5.8 across all the sets. Estimate the broad-sense heritability for seed number in this population. (4 pts) 12pt v Paragraph BIUA V V T² v B ① O wordsarrow_forward
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