ACHIEVE:INTRO TO GENETIC ANALYSIS 1TERM
12th Edition
ISBN: 9781319401399
Author: Griffiths
Publisher: MAC HIGHER
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Chapter 3, Problem 3GS
Summary Introduction
To determine: A genetic model for the inheritance of skin color explaining the wide range and show light on the popular perceptions of race and racism
Introduction: A vast range of human skin colors in which distinction can be associated, including climates, continents, and cultures, yet we know very little concerning the underlying genetic architecture.
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What is sickle cell anemia? What is the true inheritance pattern? How did scientists discover the true inheritance pattern?
Explain multiple Alleles using Human Blood Groups as an example.
Demonstrate the understanding of Polygenic Inheritance using an Example. (Skin colour or Height can be used as an example for explanation) .
What is heterozygous advantage? Provide an example to explain the process.
Male-pattern baldness is an example of a sex-influenced trait. The baldness allele, which causes hair loss, is influenced by the hormones testosterone and dihydrotestosterone, but only when levels of the two hormones are high. In general, males have much higher levels of these hormones than females, so the baldness allele has a stronger effect in males than in females. (B-baldness; N-full or normal) hair) A normal man marries a normal woman. What can be the possible genotypes of the parents respectively? *
a. BN x BN
b. NN x BN
c. NN x bb
d. NN x BB
e. BN x bb
f. BB x BB
Color-blindness is a recessive disorder found on the X chromosome. There can be individuals that are carriers for
the trait (Of the two X chromosomes they have, only one has the colorblindness allele while the other is normal.
In this pattern of inheritance, all carriers are female). We express sex-linked traits with respect to our sex
chromosomes. For example, if the allele for colorblindness is "b" and the allele for normal color vision is "B",
then a female carrier is X x.
II
III
IV
6. What are the two sex chromosomes for females?
What are the two sex chromosomes for
males?
7. Is the Generation I male colorblind?
his sex chromosomes)?.
What is his genotype (be sure to express it with regard to
8. Why are all the females in Generation II carriers? (be careful: one of the females shown "married in" to the
family)
9. The first couple in Generation II has four children. Show the genotypes of their daughters. What is the
probability their daughters will be carriers?
10. If a female…
Chapter 3 Solutions
ACHIEVE:INTRO TO GENETIC ANALYSIS 1TERM
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 43.1PCh. 3 - Prob. 43.2PCh. 3 - Prob. 43.3PCh. 3 - Prob. 43.4PCh. 3 - Prob. 43.5PCh. 3 - Prob. 43.6PCh. 3 - Prob. 43.7PCh. 3 - Prob. 43.8PCh. 3 - Prob. 43.9PCh. 3 - Prob. 43.10PCh. 3 - Prob. 43.11PCh. 3 - Prob. 43.12PCh. 3 - Prob. 43.13PCh. 3 - Prob. 43.14PCh. 3 - Prob. 43.15PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 70PCh. 3 - Prob. 1GSCh. 3 - Prob. 2GSCh. 3 - Prob. 3GS
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- Two alleles relate to melanin production A or a, where albinism is the expression of the recessive trait. If Tom is an Albino, but neither of his parents are, then what must both of their genotypes be? Group of answer choices []: AA []: aa []: None of the other answers are true []: Aaarrow_forwardBelow is examples of different genotypes and their respective dominant and recessive alleles. Predict which phenotype will be expressed for each given genotype. What are some observations you noticed between dominant and recessive alleles?arrow_forwardSkin color in humans is determined by a polygenic inheritance system. The husband is white while the wife is of Nigerian heritage. However, their two children are all light-skinned. How were the married couples able to have light-skinned babies. Are the odds to have a light-skinned baby one in a million? What are the possible genotypes of the husband and the wife and their children.arrow_forward
- in humans, normal skin pigmentation is influenced by a dominant gene (c), which allows pigmentation to develop. all individuals who are homozygous for the recessive allele (c) are unable to produce an enzyme needed for melanin formation and are therefore referred to as albino. two normal parents produce an albino child. what are the chances that the next child will be an albino? 1/2 chance 1/8 chance 2/3 chance no chance 1/4 chancearrow_forwardParents often want to know what is genetically possible for their children. If two parents are carriers for a recessive lethal trait, what are the odds that their child is also a carrier? Many times there is interest in tracking multiple traits at once (not just 1 or 2). The same probability rules apply here, you just multiple all the odds together at once. Imagine two parents. They are both carriers for red hair, one person is blood type AB, the other is type O. They want to know the odds of a daughter with red hair and type B blood. Please do no not do a giant Punnett square! Use probability or individual squares. a. What are the genotypes of the parents? b. What are the odds of each trait (daughter, red hair, type B)arrow_forwardAlbinism is inherited through a recessive allele (a). Juan has normal skin color. His Mom and Dad also have normal skin color. Juan marries Paige, who also has normal skin color. Surprisingly, their first child is an albino. What is everyone's genotype?arrow_forward
- Figure 2: This Punnett Square shows inheritance of eye color. Brown eyes (B) is dominant. Green eyes (b) is recessive. Father's Genes b BB Bb b Bb bb %24 %23 3. 7 8. 4. Barrow_forwardColor-blindness is a sex-linked trait. A boy, whose parents and grandparents had normal vision, is color-blind. What are the genotypes for his mother and his maternal grandparents? Show all workarrow_forwardAlbinism is a recessive genetic condition in which a person lacks pigment that gives color to the skin. If the allele for albinism is represented as "a," and the functional allele is represented as "A," what will be the genotype of a person with albinism? Aa or AA Aa or aa AA aaarrow_forward
- Hemophilia is a sex-linked trait. A person with hemophilia is lacking certain proteins that are necessary for normal blood clotting. Hemophilia is caused by a recessive allele so use "N" for normal and "n" for hemophilia. Since hemophilia is sex-linked, remember a woman will have two alleles (NN or Nn or nn) but a man will have only one allele (N or n). A woman who is heterozygous (a carrier) for hemophilia marries a normal man: a.What are the genotypes of the parents? b.What is the probability that a male offspring will have hemophilia? c. What is the probability of having a hemophiliac female offspring?arrow_forwardHuntington's disease is an inherited autosomal dominant disorder that can affect both men and women. Imagine a couple has had seven children, and later in life, the husband develops Huntington's disease. He is tested and it is discovered he is heterozygous for the disease allele, Hh. The wife is also genetically tested for the Huntington's disease allele, and her test results show she is unaffected, hh. What is the percent probability that the first child of this couple will have Huntington's disease? probability: % What is the percent probability that two of the seven children will have Huntington's disease? probability: %arrow_forwardAuricular hypertrichosis is a dominant Y-linked condition. Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. b C STRONGLY AGREE! STRONGLY DISAGREE! There is no such thing as a dominant or recessive Y-linked trait since only one allele is involved making this the most appropriate choice. Not enough information is provided to interpret the statement. Operarrow_forward
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