General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Question
Chapter 3, Problem 3.85SP
Interpretation Introduction
Interpretation:
The lattice energy during formation of calcium hydride from calciumand hydrogenhas to be calculated.
Concept introduction:
Lattice energy in ionic solids:
- The strength of energy of ionic bonds in a solid is known as lattice energy. It is also defined as energy required for an ionic solid to split up into single gaseous ions.
- Lattice energy increases with increase in charge of ions (that is small sized ions) and decreases with increase in ionic radii.
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Check out a sample textbook solutionStudents have asked these similar questions
Given the following values determine the lattice energy for NaCl:
Sublimation energy of Na: 108KJ/mol
Ionization energy of Na: 496KJ/mol
Bond energy of Cl2: 244KJ/mol
Electron Affinity of Cl: -349 KJ/mol
Heat of formation of NaCl: -411KJ/mol
Question 5
Suppose there is an element X which occurs naturally as X2(g).X2(g) + 2O2(g) → X2O4(g)ΔHof of O(g) is 249 kJ/molΔHof of X(g) is 458.5 kJ/molΔHof of X2O4(g) is 31 kJ/molThe X-X single bond energy is 116 kJ/molUse the above data to estimate the average bond energy in X2O4.
Give your answer to the nearest 1 kJ/mol.
Chapter 3 Solutions
General Chemistry: Atoms First
Ch. 3.1 - Prob. 3.1PCh. 3.1 - Which of the following drawings is most likely to...Ch. 3.2 - Give systematic names for the following compounds:...Ch. 3.2 - Write formulas for the following compounds: (a)...Ch. 3.2 - Prob. 3.5CPCh. 3.2 - Give systematic names for the following compounds:...Ch. 3.2 - Prob. 3.7PCh. 3.2 - Prob. 3.8CPCh. 3.3 - Predict the ground-state electron configuration...Ch. 3.3 - What doubly positive ion has the following...
Ch. 3.4 - Prob. 3.11PCh. 3.4 - which of the following spheres represents a K+...Ch. 3.5 - Using the periodic table as your guide, predict...Ch. 3.6 - (a) Which has the larger third ionization energy,...Ch. 3.6 - Three atoms have the following electron...Ch. 3.6 - Order the indicated three elements according to...Ch. 3.7 - Prob. 3.17PCh. 3.7 - Which of the indicated three elements has the...Ch. 3.8 - What noble-gas configurations are the following...Ch. 3.8 - Prob. 3.20PCh. 3.9 - Calculate the net energy change in kilojoules per...Ch. 3.10 - Which substance in each of the following pairs has...Ch. 3.10 - One of the following pictures represents NaCl and...Ch. 3.11 - Prob. 3.24PCh. 3.11 - Complete the following equations so that the same...Ch. 3.12 - Prob. 3.26PCh. 3.12 - Prob. 3.27PCh. 3.14 - Prob. 3.28PCh. 3 - In the following drawings, red spheres represent...Ch. 3 - Which of the following drawings is more likely to...Ch. 3 - Prob. 3.31CPCh. 3 - Prob. 3.32CPCh. 3 - Prob. 3.33CPCh. 3 - Prob. 3.34CPCh. 3 - Prob. 3.35CPCh. 3 - Prob. 3.36CPCh. 3 - Prob. 3.37CPCh. 3 - Prob. 3.38SPCh. 3 - Prob. 3.39SPCh. 3 - Prob. 3.40SPCh. 3 - Prob. 3.41SPCh. 3 - Prob. 3.42SPCh. 3 - Prob. 3.43SPCh. 3 - Prob. 3.44SPCh. 3 - Prob. 3.45SPCh. 3 - Prob. 3.46SPCh. 3 - Prob. 3.47SPCh. 3 - Prob. 3.48SPCh. 3 - Prob. 3.49SPCh. 3 - Prob. 3.50SPCh. 3 - Prob. 3.51SPCh. 3 - Prob. 3.52SPCh. 3 - What is the identity of the element X in the...Ch. 3 - Prob. 3.54SPCh. 3 - Prob. 3.55SPCh. 3 - Prob. 3.56SPCh. 3 - Prob. 3.57SPCh. 3 - Prob. 3.58SPCh. 3 - Prob. 3.59SPCh. 3 - Prob. 3.60SPCh. 3 - Prob. 3.61SPCh. 3 - Prob. 3.62SPCh. 3 - Prob. 3.63SPCh. 3 - Prob. 3.64SPCh. 3 - Prob. 3.65SPCh. 3 - Prob. 3.66SPCh. 3 - Prob. 3.67SPCh. 3 - Which element in each of the following sets has...Ch. 3 - Prob. 3.69SPCh. 3 - Prob. 3.70SPCh. 3 - Prob. 3.71SPCh. 3 - Prob. 3.72SPCh. 3 - Prob. 3.73SPCh. 3 - Prob. 3.74SPCh. 3 - Prob. 3.75SPCh. 3 - Prob. 3.76SPCh. 3 - Prob. 3.77SPCh. 3 - Prob. 3.78SPCh. 3 - Order the following compounds according to their...Ch. 3 - Calculate the energy change in kilojoules per mole...Ch. 3 - Prob. 3.81SPCh. 3 - Prob. 3.82SPCh. 3 - Prob. 3.83SPCh. 3 - Prob. 3.84SPCh. 3 - Prob. 3.85SPCh. 3 - Calculate the overall energy change in kilojoules...Ch. 3 - The estimated lattice energy for CsF2(s) is +2347...Ch. 3 - Prob. 3.88SPCh. 3 - Prob. 3.89SPCh. 3 - Prob. 3.90SPCh. 3 - Prob. 3.91SPCh. 3 - Prob. 3.92SPCh. 3 - Prob. 3.93SPCh. 3 - Prob. 3.94SPCh. 3 - Prob. 3.95SPCh. 3 - Prob. 3.96SPCh. 3 - Prob. 3.97SPCh. 3 - Prob. 3.98SPCh. 3 - Prob. 3.99SPCh. 3 - Prob. 3.100CHPCh. 3 - Prob. 3.101CHPCh. 3 - Prob. 3.102CHPCh. 3 - Prob. 3.103CHPCh. 3 - Prob. 3.104CHPCh. 3 - Prob. 3.105CHPCh. 3 - Prob. 3.106CHPCh. 3 - Prob. 3.107CHPCh. 3 - Prob. 3.108CHPCh. 3 - Prob. 3.109CHPCh. 3 - Prob. 3.110CHPCh. 3 - Prob. 3.111CHPCh. 3 - Prob. 3.112CHPCh. 3 - Prob. 3.113CHPCh. 3 - Prob. 3.114CHPCh. 3 - Given the following information, construct a...Ch. 3 - Given the following information, construct a...Ch. 3 - Consider the electronic structure of the element...Ch. 3 - Prob. 3.118MPCh. 3 - Prob. 3.119MP
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- Which compound in each of the following pairs of ionic substances has the most negative lattice energy? Justify your answers. a. LiF, CsF b. NaBr, NaI c. BaCl2, BaO d. Na2SO4, CaSO4 e. KF, K2O f. Li2O, Na2Sarrow_forwardCalculate the lattice energy of potassium fluoride, KF, using the BornHaber cycle. Use thermodynamic data from Appendix C to obtain the enthalpy changes for each step. (Note: You will obtain a slightly different answer if you use values given in Chapter 8 for the ionization energy and electron affinity, which are energy values at 0 K rather than the enthalpy changes at 298 K.)arrow_forwardElement First Ionization Energy (kJImol) Second Ionization Energy (kiImol) I K 419 3050 Ca 590 1140 75. Use principles of atomic structure to answer each of the following: (a) The radius of the Ca atom is 197 pm; the radius of the Ca2+ ion is 99 pm. Account for the difference. (b) The lattice energy of CaO(s) is 3460 kJ/mol; the lattice energy of K2O is 2240 kJ/mol. Account for the difference. (c) Given these ionization values, explain the difference between Ca and K with regard to their first and second ionization energies. Element First Ionization Energy (kJ/mol) Second Ionization Energy (kJ/mol) K 419 3050 Ca 590 1140 (d) The first ionization energy of Mg is 738 kJ/mol and that of Al is 578 kJ/mol. Account for this difference.arrow_forward
- Using the following data, calculate the lattice energy of calcium chloride: Ca2+(g) + 2Cl– (g) → CaCl2(s) ΔHlattice = ? Sublimation enthalpy of calcium ΔH = 177.8 kJ/mol First ionization energy of calcium ΔH = 590.2 kJ/mol Second ionization energy of calcium ΔH = 1144.2 kJ/mol First electron affinity of chlorine ΔH = –349 kJ/mol Heat of formation of CaCl2(s) ΔH = –795.4 kJ/mol Bond energy of Cl2 (see Table 2) Use Hess’s law to calculate the lattice energy of calcium chloride. set-up must show all the chemical equations and you must show how their H values add up to give your answer.arrow_forwardWhat is the lattice energy of NaCl? Use the given information below.Heat of formation for NaCl = -411.1 kJ/molHeat of sublimation for Na = 107.3 kJ/molIonization energy for Na = 496.0 kJ/molBond dissociation energy for Cl 2 = 240 kJ/molElectron affinity of Cl = -349.0 kJ/molarrow_forwardGiven the following information, find the lattice enthalpy (kJ/mol) of NaCl(s). ΔHf (NaCl) = -411 kJ/mol ΔHsublimation (Na) = 107 kJ/mol IE1 (Na) = 496 kJ/mol Bond Energy (Cl-Cl) = 244 kJ/mol EA1 (Cl) = -349 kJ/molarrow_forward
- Given the following information: Heat of sublimation of Li(s) = 166 kJ/mol Bond energy of HF = 565 kJ/mol Ionization energy of Li(g) = 520. kJ/mol Electron affinity of F(g) = –328 kJ/mol Lattice energy of LiF(s) = –1030 kJ/mol Bond energy of H2 = 432 kJ/mol Calculate the net change in energy for the following reaction: 2Li(s)+2HF(g)-> 2LiF(s) +H2(g) Change in energy = kJarrow_forwardEnter your answer in the provided box. Use the Born-Haber cycle to calculate the lattice energy of NaCl. (The heat of sublimation of Na is 108 kJ/mol and AH (NaCl) = -411 kJ/mol. Energy needed to dissociate 1/2 mole of Cl, into Cl atoms = 121.4 kJ.) kJ/molarrow_forwardN Calculate the lattice enthalpy for RbCl. You will need the following information: Species A,H, kJ/mol Rb(e) RbCl() CI(g) Enthalpy of ionization for Rb(g) is 403.0 kl/mol; electron attachment enthalpy for Cl(g) is-349.0 kJ/mol Lattice enthalpy kJ/mol Submit Answer *** 1 43 E D 80.9 -435.4 121.3 Try Another Version 80 54 R F di a 25 2 item attempts remaining T G ‹6 P FA Y & 29 7 H 8 #7 U 8 Dil FA - 6 8 Karrow_forward
- What is the lattice energy of RbBr? Use the given information below.Heat of formation for RbBr = -389.20 kJ/molHeat of sublimation for Rb = 82.00 kJ/molIonization Energy for Rb = 409.00 kJ/molBond dissociation energy for Br2 = 190.00 kJ/molElectron affinity of Br = -325.00 kJ/molHeat of vaporization for Br2 = 30.90 kJ/molarrow_forwardConsider the following information. • The lattice energy of CsCl is AH lattice = -657 kJ/mol. • The enthalpy of sublimation of Cs is AH sub = 76.5 kJ/mol. • The first ionization energy of Cs is IE₁ = 376 kJ/mol. • The electron affinity of Cl is AHEA = -349 kJ/mol. • The bond energy of Cl, is BE = 243 kJ/mol. Determine the enthalpy of formation, AH₁, for CsCl(s). AH₁ = G Search or type URL % 5 A MacBook Pro 6 & 7 * CO 8 9 O - O 0 kJ/mol A I Parrow_forward1. Below is a list of enthalpy changes for the Born-Haber cycle for the formation of solid LiF from Li(s) and F(g). Use these data to determine the lattice energy for the formation LiF(s). Li(s) → Li(g) ΔH1 = +162 kJ/mol Li(g) → Li+(g) + e- ΔH2 = +520.2 kJ/molF2(g) → 2F(g) ΔH3 = 154 kJ/mol F(g) + e- → F-(g) ΔH4 = -328 kJ/molLi(s) + 1/2F2(g) → LiF(s) ΔHf = -612 kJ/mol Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a. 1371 kJ/mol b. -1371 kJ/mol c. 1043 kJ/mol d. -1043 kJ/molarrow_forward
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