Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
2nd Edition
ISBN: 9780393655551
Author: KARTY, Joel
Publisher: W. W. Norton & Company
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Chapter 3, Problem 3.44P
Interpretation Introduction

Interpretation:

The HOMO and LUMO of the uncharged CH3CH2 molecule is to be determined.

Concept introduction:

According to VSEPR theory, atoms that are bonded to two or more other atoms are considered to be hybridized. Such atoms contribute their valence orbitals for mixing. The new orbitals are formed by mixing just two AOs. The hybridization of an atom can be determined based on the electron geometry about an atom. The electron geometry about an atom describes the orientation of group of electrons around it. MOs are constructed from the AOs of different atoms. The two atomic orbitals, on mixing along bonding axes, form two molecular orbitals – one is σ, and the other is σ*. The σ is a bonding MO, and σ* is an antibonding MO. The σ MOs have lower energy and greater stability than the corresponding σ* MOs. The highest occupied molecular orbital, i.e., the highest energy MO that contains an electron is HOMO. The lowest unoccupied molecular orbital, i.e., lowest energy MO having no electron is LUMO.

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?
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