A parallel-plate capacitor is used as a vibration sensor. The plates have an area of 100cm 2 , the dielectric is air, and the distance between the plates is a function of time given by d ( t ) = 1 + 0.01 sin ( 200 t ) m m A constant voltage of 200 V is applied to the sensor Determine the current through the sensor as a function of time by using the approximation 1 / ( 1 + x ) ≅ 1 − x for x < < 1 . (The argument of the sinusoid is in radians.)
A parallel-plate capacitor is used as a vibration sensor. The plates have an area of 100cm 2 , the dielectric is air, and the distance between the plates is a function of time given by d ( t ) = 1 + 0.01 sin ( 200 t ) m m A constant voltage of 200 V is applied to the sensor Determine the current through the sensor as a function of time by using the approximation 1 / ( 1 + x ) ≅ 1 − x for x < < 1 . (The argument of the sinusoid is in radians.)
Solution Summary: The author calculates the capacitance of a parallel-plate capacitor used as an vibration sensor. The current through the capacitor in terms of time is given by I=(-epsilon _0
A parallel-plate capacitor is used as a vibration sensor. The plates have an area of
100cm
2
, the dielectric is air, and the distance between the plates is a function of time given by
d
(
t
)
=
1
+
0.01
sin
(
200
t
)
m
m
A constant voltage of 200 V is applied to the sensor Determine the current through the sensor as a function of time by using the approximation
1
/
(
1
+
x
)
≅
1
−
x
for
x
<
<
1
. (The argument of the sinusoid is in radians.)
Calculate the voltage at 1.5¹ (milliseconds) for the following RC Circuit. Assume switch is closed and capacitor is in a charge
state.
t=0
LE
-10 V
oto
R1
1kQ
C1
1uF
Oscilloscope-XSC1
MAAA
Channel B
643.751 mV
643.751 mV
0.000 V
T1
T2
T2-T1
Time
379.198 ms
379.198 ms
0.000 s
Timebase
Scale: 500 us/Div
X pos.(Div): 0
Y/T Add B/A A/B
Discussion
Channel A
1.086 V
1.086 V
0.000 V
Channel A
Scale: 1 V/Div
Y pos.(Div): 0
AC 0 DC
●
Channel B
Scale: 1 V/Div
Y pos.(Div): 0
AC 0 DC
Reverse
Save
Trigger
Ext. trigger
Edge:
fz
B Ext
Level:
0
V
Single Normal Auto None
ZA
X
Fig(6): The input and output waveforms for differentiator Operational Amplifier
1- If Op Amp is operating at 1000 Hz as input wave, what is the frequency of the output
signal?
2- Why do we use Spike function? List the possible application of spike waveform.
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