Chapter 3, Problem 3.27E

(a)

Interpretation Introduction

Interpretation:

Surface area of $\text{2,2-dimethylpropane}$ and pentane has to be determined.

Concept Introduction:

Expression to determine surface area of sphere is as follows:

  $\text{Surface area}=4\text{π}{r}^2$        (1)

Here,

$r$ is radius of sphere.

Expression to determine surface area of rectangular prism is as follows:

  $\text{Surface area}=2\left(wl+hl+hw\right)$        (2)

Here,

$w$ is width.

$l$ is length.

$h$ is height.

(b)

Interpretation Introduction

Interpretation:

Whether $\text{2,2-dimethylpropane}$ or pentane has higher surface area has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Whether $\text{2,2-dimethylpropane}$ or pentane has higher boiling point has to be determined.

Concept Introduction:

Boiling point is measure of intermolecular forces. It also depends on dipole moment and masses of molecules. Smaller molecules have high thermal motion and therefore these have lower boiling points and vice-versa. So boiling point is directly related to masses of molecules. Molecule with large surface area has high tendency to interact with other molecules. Since boiling point depends on strength of intermolecular forces, it has high boiling point.