
Concept explainers
(a)
Interpretation:
The Lewis structure for cyclopropane having molecular formula C3 H6 is to be drawn.
Concept Introduction:
During the formation of a compound each atom tends to lose, gain or share enough electrons to achieve an electronic configuration having eight valence electrons. This rule is also known as octet rule. The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
A Lewis structure is representation of distribution of electrons on each atom of the molecule. Some of the electrons are shared by atoms to form bonds and some exist as lone pair which do not take part in bonding.
(b)
Interpretation:
Using VSEPR Theory, the geometry of each central atom present in given structure of Cyclopropane is to be identified.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(c)
Interpretation:
Using VSEPR theory, the various relative bond angles associated with each central atom of the Cyclopropane molecule is to be determined.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(d)
Interpretation:
Observing the given the shape and size of the Cyclopropane ring, the bond angle for C−C−C is to be predicted.
Concept Introduction:
Bond angle of the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model.
(e)
Interpretation:
A proper explanation with reason is to be given, why cyclopropane is considerably less stable than other three-carbon compounds that do not contain a ring.
Concept Introduction:
Bond angle of the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model.

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Chapter 3 Solutions
Introduction To General, Organic, And Biochemistry
- QUESTION 1 Write the IUPAC names for the following compounds. (a) (b) 2 H₂C CH (c) Br (d) HO (e) COOHarrow_forwardneed help finding the product of these reactionsarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism 1) Bakelite like polymer Using: Resorcinol + NaOH + Formalin 2) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerol 3) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium boratearrow_forward
- Using the table of Reactants and Products provided provide the correct letter that corresponds with the Carboxylic acid that is formed in the reaction below. 6 M NaOH Acid-workup WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR PHRASES A) Pool of Reagents for Part B CI B) OH C) E) CI J) racemic F) K) OH N) OH P) G) OH D) HO H) L) M) HO Q) R) CI Aarrow_forwardIn the table below, the exact chemical structures for Methyl salicylate can be represented by the letter WRITE THE CORRECT LETTER ONLY DO NOT WRITE EXTRA WORDS OR PHRASES CI B) A) E) Cl racemic F) J) CI K) N) OH P) Pool of Reagents for Part B OH OH G) L) OH D) HO H) M) HO Q) R) CIarrow_forwardDraw the stepwise mechanism for the reactionsarrow_forward
- Part I. a) Draw reaction mechanism for the transformations of benzophenone to benzopinacol to benzopinaco lone b) Pinacol (2,3-dimethyl, 1-3-butanediol) on treatment w/ acid gives a mixture of pina colone (3,3-dimethyl-2-butanone) and 2, 3-dimethyl - 1,3-butadiene. Give reasonable mechanism the formation of the products Forarrow_forward3. The explosive decomposition of 2 mole of TNT (2,4,6-trinitrotoluene) is shown below: Assume the C(s) is soot-basically atomic carbon (although it isn't actually atomic carbon in real life). 2 CH3 H NO2 NO2 3N2 (g)+7CO (g) + 5H₂O (g) + 7C (s) H a. Use bond dissociation energies to calculate how much AU is for this reaction in kJ/mol.arrow_forwardPart I. Draw reaction mechanism for the transformations of benzophenone to benzopinacol to benzopinaco lone and answer the ff: Pinacol (2,3-dimethyl, 1-3-butanediol) on treatment w/ acid gives a mixture of pina colone and (3,3-dimethyl-2-butanone) 2,3-dimethyl-1,3-butadiene. Give reasonable mechanism the formation of the products Forarrow_forward
- Show the mechanism for these reactionsarrow_forwardDraw the stepwise mechanismarrow_forwardDraw a structural formula of the principal product formed when benzonitrile is treated with each reagent. (a) H₂O (one equivalent), H₂SO₄, heat (b) H₂O (excess), H₂SO₄, heat (c) NaOH, H₂O, heat (d) LiAlH4, then H₂Oarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
