
Concept explainers
(a)
Interpretation:
Using VSEPR Theory, the geometry of each central atom present in given structure of Androstenedione is to be identified.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(b)
Interpretation:
Using VSEPR theory, the various relative bond angles associated with each central atom of the Androstenedione molecule is to be determined.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
1. Each carbon atom having all single bonds having tetrahedral geometry has bond angle
2. Each carbon atom having double bond having trigonal planner geometry has bond angle 120(.
(c)
Interpretation:
The most polar bond in androstenedione is to be predicted.
Concept Introduction:
A molecule is polar if it has polar bonds and the centers of its partial positive and partial negative charge do not coincide.
(d)
Interpretation:
Observing the bonds of Androstenedione molecule, it should be determined whether Androstenedione is polar or nonpolar.
Concept Introduction:
A molecule is polar if it has polar bonds and if the centers of partial positive charge and partial negative charge lie at different places with in the molecule.

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Chapter 3 Solutions
Introduction To General, Organic, And Biochemistry
- Stuc X ctclix ALE X A ALE אן A ALEX Lab (195 X Nut x M Inb x NU X NUT X Unt x + → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpZuyrVCdQolLAKqp_7U3r1GUD3... New Chrome available: Naomi Question 26 of 39 (4 points) | Question Attempt: 1 of Unlimited Give the IUPAC name. 2,3-dimethylhexane Part: 1/2 Part 2 of 2 Draw the skeletal structure of a constitutional isomer of the alkane above that contains a different number of carbons in its longest chain. Skip Part Check Click and drag to start drawing a structure. 3 Finance headline Q Search mwa Harvard Intensifi... X Save For Later 00 dlo HB Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility a 9:11 PM 4/22/2025arrow_forwardPredict the product of this organic reaction: + NH2 HO A P+ H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Click and drag to start drawing a structure. ✓arrow_forward个 Stuc X ctclix ALE X A ALE × A ALE X Lab x (195 × Nut x M Inbx EF 目 → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpz Chapter 12 HW = Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited Part: 1/2 Part 2 of 2 Give the IUPAC name. Check 3 50°F Clear ©2025 McGraw Hill L Q Search webp a عالياكarrow_forward
- 个 Stuck x ctc xALE X A ALE × A ALE X Lab x (19: x - G www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-1Q1g8NUi-mObka ZLx2twjEhK7mVG6PUUIO06 Chapter 12 HW 三 Question 26 of 39 (4 points) 1 Question Attempt: 1 of Unlimited Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Give the IUPAC name. Skip Part 2 53°F Clear Check × Q Search hp hp 02arrow_forwardCalculate the equilibrium constant at 25.0 oC for the following equation. Cd(s) + Sn+2(aq) ↔Cd+2(aq) + Sn(s) Group of answer choices 3.11x104 1.95x1018 9.66x108 1.40x109arrow_forwardWhat is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forward
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
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