
(a)
Interpretation:
The name of compound using Roman numeral to show the charge on a
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(b)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(c)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(d)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(e)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.
(f)
Interpretation:
The name of compound using Roman numeral to show the charge on a transition metal ion should be identified.
Concept Introduction:
The name of the compound written by writing the name of cation followed by the name of anion with either suffix -ate or -ide depending upon the group to which the atom belongs. The name of the cation is written same as the name of metal. The charge on the metal atom is its oxidation state and it can be written in roman numeral as follows:
1-(I), 2-(II), 3-(III), 4-(IV) and so on.

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Chapter 3 Solutions
Introduction To General, Organic, And Biochemistry
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- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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