(a) Interpretation: Using VSEPR Theory, the geometry of each central atom present in given structure of ATP is to be identified. Concept Introduction Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
(a) Interpretation: Using VSEPR Theory, the geometry of each central atom present in given structure of ATP is to be identified. Concept Introduction Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
Solution Summary: The author explains how bond angles in molecules can be predicted using valence shell electron pair repulsion (VSEPR) model.
Using VSEPR Theory, the geometry of each central atom present in given structure of ATP is to be identified.
Concept IntroductionBond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
Interpretation Introduction
(b)
Interpretation:
Using VSEPR theory, the various relative bond angles associated with each central atom of the ATP molecule is to be determined.
Concept Introduction:
Bond angles in the molecules can be predicted by using valence shell electron pair repulsion (VSEPR) model. According to this model, the valence electrons of an atom are involved in the formation of single, double or triple bond. The valence electrons can also be unshared and exist as lone pair on atoms. The combination forms a negatively charged region of electron density around a nucleus. Since, like charges do not attract, the region of electron density around a nucleus spread out so that each atom is as far away from each other at different angles.
Interpretation Introduction
(c)
Interpretation:
The most polar bond in ATP is to be predicted.
Concept Introduction:
A molecule is polar if it has polar bonds and the centers of its partial positive and partial negative charge do not coincide.
Interpretation Introduction
(d)
Interpretation:
Observing the bonds of ATP molecule, it has to be determined whether ATP is polar or nonpolar.
Concept Introduction:
A molecule is polar if it has polar bonds and if the centers of partial positive charge and partial negative charge lie at different places with in the molecule.
Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore
inorganic byproducts.
Incorrect, 5 attempts remaining
1. NaOCH3/CH3OH
2. Acidic workup
Select to Draw
O
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The total number of carbons in the parent chain is incorrect. Review the reaction conditions including starting materials and/or
intermediate structures and recount the number of carbon atoms in the parent chain of your structure.
OK
Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40.
a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L)
b) Calculate the molar absorptivity, a, of the 1645 cm-1 band
c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c
d) Calculate x for the 1645 cm-1 band
Convert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).
Chapter 3 Solutions
Introduction To General, Organic, And Biochemistry
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