Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Textbook Question
Chapter 28, Problem 7P
The Roles of Helicases and Gyrases How do DNA gyrases and helicases differ in their respective functions and modes of action?
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Chapter 28 Solutions
Biochemistry
Ch. 28 - Semiconservative or Conservative DNA Replication...Ch. 28 - The Enzymatic Activities of DNA Polymerase I (a)...Ch. 28 - Multiple Replication Forks in E. coli I Assuming...Ch. 28 - Multiple Replication Forks in E. coli II On the...Ch. 28 - Molecules of DNA Polymerase III per Cell vs....Ch. 28 - Number of Okazaki Fragments in E. coli and Human...Ch. 28 - The Roles of Helicases and Gyrases How do DNA...Ch. 28 - Human Genome Replication Rate Assume DNA...Ch. 28 - Heteroduplex DNA Formation in Recombination From...Ch. 28 - Homologous Recombination, Heteroduplex DNA, and...
Ch. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Chemical Mutagenesis of DNA Bases Show the...Ch. 28 - Prob. 14PCh. 28 - Recombination in Immunoglobulin Genes If...Ch. 28 - Helicase Unwinding of the E. coli Chromosome...Ch. 28 - Prob. 17PCh. 28 - Functional Consequences of Y-Family DNA Polymerase...Ch. 28 - Figure 28.11 depicts the eukaryotic cell cycle....Ch. 28 - Figure 28.41 gives some examples of recombination...Ch. 28 - Prob. 21PCh. 28 - Prob. 22P
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- Why are most DNA-binding proteins specific to certain chemicalgroups within the DNA?arrow_forwardWhat entropic factor destabilizes helical DNA at high temperature?arrow_forward54.5-methylcytosine results from which of the following events? O phosphorylation of cytosine base in DNA O methylation of guanine base in DNA Omethylation of cytosine base in DNA O alkylation of cytosine base in DNA O de-methylation of cytosine in DNAarrow_forward
- The High Mobility Group (HMG) proteins are architectural regulators of DNA. Many HMG proteins are phosphorylated at certain serine residues. How would phosphorylation change the binding affinity of HMG proteins to DNA?arrow_forwardEnediynes are natural products with potent antitumor properties because they are able to cleave DNA (page 288). Their cytotoxic properties are due tothe enediyne undergoing a cyclization to form a highly reactive diradical intermediate. The intermediate abstracts hydrogen atoms from the backbone of DNA, which triggers its damage. Draw the structure of the diradical intermediate.arrow_forwardBearing in mind the different number of hydrogen bonds that form between the two different purine- pyrimidine pairs in DNA, how would you explain the fact that DNA that is rich in cytosine-guanine pairs requires heating to a slightly higher temperature in order to separate the strands than DNA that is rich in adenine-thymine pairs?arrow_forward
- DNA ligase has the ability to relax supercoiled circular DNA in the presence of AMP but not in its absence. (a) What is the mechanism of this reaction, and why is it dependent on AMP? (b) How might one determine that supercoiled DNA had in fact been relaxed?arrow_forwardExamination of the structure of DNA polymerases bound to nucleotide analogs reveals that conserved residues come within van der Waals contact of C-2' of the bound nucleotide. What is the potential significance of this interaction?arrow_forwardWhy is it necessary for naturally occurring DNA molecules to be negatively supercoiled?arrow_forward
- How the conformational changes impact its affinity for the target DNAsequence ?arrow_forwardIn E. coli, all newly synthesized DNA appears to be fragmented (an observation that could be interpreted to mean that the leading strand as well as the lagging strand is synthesized discontinuously). However, in E. coli mutants that are defective in uracil–DNA glycosylase, only about half the newly synthesized DNA is fragmented. Explain.arrow_forwardAlthough DNA polymerases require both a template and a primer, the following single-stranded polynucleotide was found to serve as a substrate for DNA polymerase in the absence of any additional DNA.3′ HO-ATGGGCTCATAGCCGGAGCCCTAACCGTAGACCACGAATAGCATTAGG-p 5′What is the structure of the product of this reaction?arrow_forward
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