Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
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Chapter 28, Problem 10P
Homologous Recombination, Heteroduplex DNA, and Mismatch Repair Homologous recombination in E. coli leads to the formation of regions of heteroduplex DNA. By definition, such regions contain mismatched bases. Why doesn’t the mismatch repair system of E. coli eliminate these mismatches?
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Chapter 28 Solutions
Biochemistry
Ch. 28 - Semiconservative or Conservative DNA Replication...Ch. 28 - The Enzymatic Activities of DNA Polymerase I (a)...Ch. 28 - Multiple Replication Forks in E. coli I Assuming...Ch. 28 - Multiple Replication Forks in E. coli II On the...Ch. 28 - Molecules of DNA Polymerase III per Cell vs....Ch. 28 - Number of Okazaki Fragments in E. coli and Human...Ch. 28 - The Roles of Helicases and Gyrases How do DNA...Ch. 28 - Human Genome Replication Rate Assume DNA...Ch. 28 - Heteroduplex DNA Formation in Recombination From...Ch. 28 - Homologous Recombination, Heteroduplex DNA, and...
Ch. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Chemical Mutagenesis of DNA Bases Show the...Ch. 28 - Prob. 14PCh. 28 - Recombination in Immunoglobulin Genes If...Ch. 28 - Helicase Unwinding of the E. coli Chromosome...Ch. 28 - Prob. 17PCh. 28 - Functional Consequences of Y-Family DNA Polymerase...Ch. 28 - Figure 28.11 depicts the eukaryotic cell cycle....Ch. 28 - Figure 28.41 gives some examples of recombination...Ch. 28 - Prob. 21PCh. 28 - Prob. 22P
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- f. The genetic code is given below, along with a short strand of template DNA. Write the protein segment that would form from this DNA. 5'-A-T-G-G-C-T-A-G-G-T-A-A-C-C-T-G-C-A-T-T-A-G-3' Table 4.5 The genetic code First Position Second Position (5' end) U C A G Third Position (3' end) Phe Ser Tyr Cys U Phe Ser Tyr Cys Leu Ser Stop Stop Leu Ser Stop Trp UCAG Leu Pro His Arg His Arg C Leu Pro Gln Arg Pro Leu Gin Arg Pro Leu Ser Asn Thr lle Ser Asn Thr lle Arg A Thr Lys UCAG UCAC G lle Arg Thr Lys Met Gly Asp Ala Val Gly Asp Ala Val Gly G Glu Ala UCAC Val Gly Glu Ala Val Note: This table identifies the amino acid encoded by each triplet. For example, the codon 5'-AUG-3' on mRNA specifies methionine, whereas CAU specifies histidine. UAA, UAG, and UGA are termination signals. AUG is part of the initiation signal, in addition to coding for internal methionine residues. Table 4.5 Biochemistry, Seventh Edition 2012 W. H. Freeman and Company B eviation: does it play abbreviation:arrow_forwardAnswer all of the questions please draw structures for major productarrow_forwardfor glycolysis and the citric acid cycle below, show where ATP, NADH and FADH are used or formed. Show on the diagram the points where at least three other metabolic pathways intersect with these two.arrow_forward
- answer the questions please all of them should be answeredarrow_forwardBurk plot is shown below. Calculate Km and max for this enzyme. show workarrow_forwardInsert Format Tools Extensions Help Normal text ▾ Arial C 2 10 3 + BIUA Student Guide (continued) Record data and conclusions about the mystery food sample either below or in a lab notebook. Step 2: Protein Test (Biuret Solution) Gelatin Water [Mystery Food (Positive Control) (Negative Control) Sample pink purple no change no change They mystery food sample does not contain protein because the color of the test tube wasn't pink or purple Color Conclusion They mystery food sample does not contain protein because the color of the test tube wasn't pink or purple Step 3: Lipid Test (Sudan Red Solution) Vegetable Oil Water (Positive Control) (Negative Control) Mystery Food Sample floating red no change floating red the mystery food dosnt contain lipids because the test tube has floating red 75 % 87 8 9 7 ChromeOS C Device will pow 26.battery lea powerarrow_forward
- The rate data from an enzyme catalyzed reaction with and without an inhibitor present is found in the image. Question: what is the KM and Vm and the nature of inhibitionarrow_forward1. Estimate the concentration of an enzyme within a living cell. Assume that: (a): fresh tissue is 80% water and all of it is intracellular (b): the total soluble protein represents 15% of the weight (c): all the soluble proteins are enzymes (d): the average molecular weight of the proteins is 150,000 (E): about 100 different enzymes are present please help I am lostarrow_forwardPlease helparrow_forward
- The following data were recorded for the enzyme catalyzed conversion of S -> P. Question: Estimate the Vmax and Km. What would be the rate at 2.5 and 5.0 x 10-5 M [S] ?arrow_forwardPlease helparrow_forwardThe following data were recorded for the enzyme catalyzed conversion of S -> P Question: what would the rate be at 5.0 x 10-5 M [S] and the enzyme concentration was doubled? Also, the rate given in the table is from product accumulation after 10 minuets of reaction time. Verify these rates represent a true initial rate (less than 5% turnover). Please helparrow_forward
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