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In places such as hospital operating rooms or factories for electronic circuit boards, electric sparks must be avoided. A prison standing on a grounded floor and touching nothing else can typically have a body capacitance of 150 pF, in parallel with a foot capacitance of 80.0 pF produced by the dielectric soles of his or her shoes. The person acquires static electric charge from interactions with Ills or her surroundings. The static charge flows to ground through the equivalent resistance of the two shoe soles in parallel with each other. A pair of rubber-soled street shoes can present an equivalent resistance of 5.00 × 103 MΩ. A pair of shoes with special static-dissipative soles can have an equivalent resistance of 1.00 MΩ. Consider the person’s body and shoes as forming an RC circuit with the ground. (a) How long does it take the rubber-soled shoes to reduce a person’s potential from 3.00 × 103 V to 100? (b) How long does it take the static-dissipative shoes to do the same thing?
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Chapter 28 Solutions
Physics for Scientists and Engineers, Technology Update (No access codes included)
- A converging lens with a focal length of 6.70 cm forms an image of a 4.60 mm tall real object that is to the left of the lens. The image is 1.50 cm tall and erect. Where are the object and image located? Is the image real or virtual? Please show all stepsarrow_forwardNo chatgpt pls will upvotearrow_forwardneed help part earrow_forward
- Critical damping is the case where the mass never actually crosses over equilibrium position, but reaches equilibrium as fast as possible. Experiment with changing c to find the critical damping constant. Use the same initial conditions as in the last problem. Zoom in a bit to make sure you don't allow any oscillations to take place - even small ones.arrow_forwardNASA's KC-135 Reduced Gravity Research aircraft, affectionately known as the "Vomit Comet," is used in training astronauts and testing equipment for microgravity environments. During a typical mission, the aircraft makes approximately 30 to 40 parabolic arcs. During each arc, the aircraft and objects inside it are in free-fall, and passengers float freely in apparent "weightlessness." The figure below shows the altitude of the aircraft during a typical mission. It climbs from 24,000 ft to 30,850 ft, where it begins a parabolic arc with a velocity of 155 m/s at 45.0° nose-high and exits with velocity 155 m/s at 45.0° nose-low. 31 000 45° nose high 45° nose low 24 000 Zero g 65 Maneuver time (s) (a) What is the aircraft's speed (in m/s) at the top of the parabolic arc? 110.0 m/s (b) What is the aircraft's altitude (in ft) at the top of the parabolic arc? 2.04e+04 What is the initial height at the start of the parabolic arc? What is the initial velocity at this point? What is the final…arrow_forward12. What could we conclude if a system has a phase trajectory that sweeps out larger and larger area as time goes by?arrow_forward
- need help part darrow_forwardA cab driver heads south with a steady speed of v₁ = 20.0 m/s for t₁ = 3.00 min, then makes a right turn and travels at v₂ = 25.0 m/s for t₂ = 2.80 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.80-min trip, calculate the following. Assume +x is in the eastward direction. (a) total vector displacement (Enter the magnitude in m and the direction in degrees south of west.) magnitude direction For each straight-line movement, model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the starting point be the origin of your coordinate system. Use the relationship speed = distance/time to find the distances traveled during each segment. Write the displacement vector, and calculate its magnitude and direction. Don't forget to convert min to s! m Model the car as a particle under constant velocity, and draw a diagram of the displacements, labeling the distances and angles. Let the…arrow_forwardî A proton is projected in the positive x direction into a region of uniform electric field E = (-5.50 x 105) i N/C at t = 0. The proton travels 7.20 cm as it comes to rest. (a) Determine the acceleration of the proton. magnitude 5.27e13 direction -X m/s² (b) Determine the initial speed of the proton. 8.71e-6 magnitude The electric field is constant, so the force is constant, which means the acceleration will be constant. m/s direction +X (c) Determine the time interval over which the proton comes to rest. 1.65e-7 Review you equations for constant accelerated motion. sarrow_forward
- Three charged particles are at the corners of an equilateral triangle as shown in the figure below. (Let q = 2.00 μC, and L = 0.750 m.) y 7.00 με 60.0° L 9 -4.00 μC x (a) Calculate the electric field at the position of charge q due to the 7.00-μC and -4.00-μC charges. 112 Once you calculate the magnitude of the field contribution from each charge you need to add these as vectors. KN/CI + 64 × Think carefully about the direction of the field due to the 7.00-μC charge. KN/Cĵ (b) Use your answer to part (a) to determine the force on charge q. 240.0 If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mN Î + 194.0 × If you know the electric field at a particular point, how do you find the force that acts on a charge at that point? mNarrow_forwardIn the Donkey Kong Country video games you often get around by shooting yourself out of barrel cannons. Donkey Kong wants to launch out of one barrel and land in a different one that is a distance in x of 9.28 m away. To do so he launches himself at a velocity of 22.6 m/s at an angle of 30.0°. At what height does the 2nd barrel need to be for Donkey Kong to land in it? (measure from the height of barrel 1, aka y0=0)arrow_forwardFor which value of θ is the range of a projectile fired from ground level a maximum? 90° above the horizontal 45° above the horizontal 55° above the horizontal 30° above the horizontal 60° above the horizontalarrow_forward
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