PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 25, Problem 94P
To determine
The value of the internal resistance in the D’ Arsonval galvanometer
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Construct Your Own Problem. Consider a battery used to supply energy to a cellular phone. Construct a problem in which you determine the energy that must be supplied by the battery, and then calculate the amount of charge it must be able to move in order to supply this energy. Among the things to be considered are the energy needs and battery voltage. You may need to look ahead to interpret manufacturer’s battery ratings in ampere-hours as energy in joules.
Pro bro hero expert Hand written solution is not allowed.
Problem 10: If you try and measure the voltage of a battery with a
voltmeter connected in series, you won't get a completely accurate
measurement because of the internal resistance of the battery. To see
how large this effect is, consider trying to measure the terminal voltage
of a 1.585 V alkaline cell having an internal resistance of 52 2 by placing
a 0.95 k2 voltmeter across its terminals.
Randomized Variables
ww
R = 0.95 k2
r = 52 Q
r
emf
Part (a) What current flows in A?
Numeric : A numeric value is expected and not an expression.
I =
Part (b) Find the terminal voltage in V.
Numeric : A numeric value is expected and not an expression.
V =
Part (c) To see how close the measured terminal voltage is to the emf, calculate their ratio.
Numeric : A numeric value is expected and not an expression.
V/e =
Chapter 25 Solutions
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) Find the current in each resistor of Figure P18.18 by using the rules for resistors in series and parallel. (b) Write three independent equations for the three currents using Kirchhoffs laws: one with the node rule; a second using the loop rule through the battery, the 6.0- resistor, and the 24.0- resistor; and the third using the loop rule through the 12.0- and 24.0- resistors. Solve to check the answers found in part (a). Figure Pl8.18arrow_forwardFigure P18.26 shows a voltage divider, a circuit used to obtain a desired voltage Vout from a source voltage . Determine the required value of R2 if = 5.00 V, Vout = 1.50 V and R1 = 1.00 103 (Hint: Use Kirchhoff's loop rule, substituting Vout = IR2, to find the current. Then solve Ohms law for R2. Figure P18.26arrow_forwardA 1.50 mF capacitor is charging through a 12.0 Ω resistorusing a 10.0 V battery. What will be the current when the capacitorhas acquired 1/4of its maximum charge? Will it be 1/4of the maximumcurrent?arrow_forward
- A 10-V battery, a 50-Ω resistor, a 0.1 F capacitor and a switch are connected in series. Initially the switchis open and the capacitor is uncharged. What is the magnitude of the voltage across ε?arrow_forwardA capacitor with a capacitance of 3.5 uF is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor with a resistance of 10.5 kOhm, and a battery that has a potential difference of 105V. (a) Immediately after the switch is closed, what is the voltage drop VC, in volts, across the capacitor? (b) Immediately after the switch is closed, what is the voltage drop VR, in volts, across the resistor? (c) Immediately after the switch is closed, what is the current, in amperes, through the resistor? (d) Find an expression for the time after the switch is closed when the current in the resistor equals half its maximum value. (e) What is the charge Q, in microcoulombs, on the capacitor when the current in the resistor equals one half its maximum value.arrow_forwardDon't use chat gpt It Chatgpt means downvotearrow_forward
- Your flashlight is getting dimmer and dimmer, so you assume the batteries are nearly dead. They are “D” cells producing 1.5 volts. You take the batteries out and test them with a voltmeter. The meter reveals the batteries have nearly 1.5 volts of potential. Are the batteries dead or is something else going on? Discuss how you can tell whether the batteries are dead, and how you would test the flashlight to see whether there is some internal problem. Is it an either-or proposition? Explain.arrow_forwardA defibrillation unit used to electrically stimulate the heart muscles following a heart attack consistsa 20-µF capacitor charged by a 6000-V potential difference. (a) Calculate the energy released whenthe defibrillator is discharged through the body. (b) How much charge is released? A 0.20-µF capacitor is to be charged through a resistor so that it becomes 63 percent charged in0.10 s. What should the resistance of the capacitor be? (b) What is the time constant if the capacitoris charged through a 20-MΩ resistor?arrow_forwardA capacitor used to provide steady voltages in the power supply of a stereo amplifier charges rapidly to 35 V every 1/60 second. It must then hold that voltage to within 1.0 V for the next 1/60 s while it discharges through the amplifier. If the amplifier draws 1.2 A from the 35-V supply, (a) what’s its effective resistance, and (b) what capacitance is needed?arrow_forward
- What is the maximum voltage that can be applied to a 186 k ohm resistor rated at 16 watts? Give your answer as an exact number. Your Answer: Answerarrow_forwardMy homework asks : rest is given in the question. Can you help with my homework? In the circuit in the figure, two identical parallel metallic plates, with identical etallic arcIt has been connected to 100 V battery. Switch on position, plates unloaded,the gap between them is d = 4 mm and the surface of one plate is 1778 m2.When the switch is turned off, the distance between the plates is reduced by 0.5 times. EachWhat is the spring constant of a spring in units of Newton / meter? Eo = 9 x 10-12 C2 / Nm2arrow_forwardA circuit you’re building needs a voltmeter that goes from 0 V to a full-scale reading of 5.0 V. Unfortunately, the only meter in the storeroom is an ammeter that goes from 0 μA to a full-scale reading of 500 μA. It is possible to use this meter to measure voltages by putting it in a measuring circuit as shown. What value of R must you use so that the meter will go to full scale when the potential difference ΔV is 5.0 V? Assume that the ammeter is ideal.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY