PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
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Chapter 25, Problem 104P
(a)
To determine
The battery current just after closing switch S.
(b)
To determine
The battery current a long time after closing the switch S.
(c)
To determine
The current through
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Chapter 25 Solutions
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
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- When the switch is open in Figure 18.8, power Po is delivered to the resistor R1. When the switch is closed, which of the following is true about the power Pc delivered to R1? (Neglect the internal resistance of the battery.) (a) Pc Po (b) Pc = Po (c) Pc Po Figure 18.8 (Quick Quizzes 18.5 and 18.6)arrow_forwardConsider the circuit in Figure 21.29 and assume the batter has no internal resistance. (i) Just after the switch is closed, what is the current in the battery? (a) 0 (b) /2R (c) 2/R (d) /R (e) impossible to determine (ii) After a very long time, what is the current in the battery? Choose from the same choices.arrow_forward(a) Find the current in each resistor of Figure P18.18 by using the rules for resistors in series and parallel. (b) Write three independent equations for the three currents using Kirchhoffs laws: one with the node rule; a second using the loop rule through the battery, the 6.0- resistor, and the 24.0- resistor; and the third using the loop rule through the 12.0- and 24.0- resistors. Solve to check the answers found in part (a). Figure Pl8.18arrow_forward
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- A battery with emf E and internal resistance r is first connectedto a resistor of resistance R1 = R, where R is greater than r.This resistor is then disconnected from the battery and replaced with aresistorof resistance R2 = 2R. Find the ratio of the power dissipated in the second resistor to the power dissipated in the first resistor.arrow_forwardConsider the circuit shown in the diagram. Before the switch is cksed, both capacitors are uncharged. V = 6 V G = 3.0 pl G = 3.5 pF R, = 80 2 R = 302 R, = 60 2 Immediately after the switch is closed, what is the amount of current supplied by the batiery? Imita = A Assuming the switch remains closed for a kong time, which capacitor will be the lirst to reach 95% of its final charge level? What is the time constant for charging this capacitor?arrow_forwardIn the circuit diagram shown in figure, R=102, L=5H, E = 20 V, i = 2 A. This current is decreasing at a rate of -1.0 A/s. Find Vab at this instant. a R ww M L ooooooo E barrow_forward
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