Chapter 25, Problem 93A

(a)

To determine

To calculate:

The power supplied to the ovens.

Answer to Problem 93A

The power supplied to the ovens is $2.88$ m/s.

Explanation of Solution

Given:

For an oven,

Number of Homes: $8$

Input for Secondary: $35$ A

Voltage for Secondary: $240$ V

Formula used:

The formula to calculate power supplied is,

  $P_s=\left(n\right)\times V_s{I}_s$

Where,

  $I_s$ : Input current for secondary

  $V_s$ : Voltage of secondary

  $n$ : Number of Homes

Calculation:

To calculate the speed,

  $P_s=\left(n\right)\times V_s{I}_s$

Substituting the above values in the equation,

  $v=\left(0.60\right)\times \left(4.8\right)=2.88$ m/s

Conclusion:

The power supplied to the ovens is $2.88m/s$ .

(b)

To determine

To calculate:

The time period of the wave.

Answer to Problem 93A

The time period of wave is $0.21m/s$ .

Explanation of Solution

Given:

  $f$ : Frequency = $4.8$

Formula used:

To calculate the time period formula is,

  $T=\frac{1}{f}$

Where,

  $f$ : Frequency

T: Time

Calculation:

The rate of oscillation is given as $4.8$ $m/s$ ,

Now, to calculate the period substitute the values in the above formula

  $T=\frac{1}{f}$

  $T=\frac{1}{4.8}$

  $T$ = $0.21$ m/s

Conclusion:

Hence the period of wave is $0.21$ m/s.