Chapter 25, Problem 72A

To determine

To Explain:

Construct a reverse problem.

Answer to Problem 72A

Consider a metal rod of length $0.8$ m and moves to its left direction under the magnetic field of strength $0.15$ T. The direction of the magnetic field is upwards. The induced potential is of about $6.5$ V, calculate the speed of the wire with which it moves.

Explanation of Solution

Introduction:

Conversion of energy from one form to another takes place in the generator or battery as the device works on the electric charge that is transferred within itself.

  $EMF=BLv(sin\theta )$

Where,

  $EMF$ : Electromotive force

  $B$ : Magnetic field

  $L$ : Length

  $v$ : Velocity

The value of $\sin \theta$ is 1 as the direction across the field is perpendicular.

Velocity is the speed.

  $EMF$ is given as ,

  $EMF=BLv\left(\sin \theta \right)$

The given equation is in terms of velocity.

Thus rearranging the above equation,

  $v=\frac{EMF}{B\times L}$

Now the solution to satisfy the given equation can be ,

A metal rod of length $0.8$ m and moves to its left direction under the magnetic field of strength $0.15$ T. The direction of the magnetic field is upwards. The induced potential is of about $6.5$ V, calculate the speed of the wire with which it moves.

Conclusion:

Hence, the constructed question for the given situation is:

A metal rod of length $0.8$ m and moves to its left direction under the magnetic field of strength $0.15$ T. The direction of the magnetic field is upwards. The induced potential is of about $6.5$ V, calculate the speed of the wire with which it moves.