Chapter 25, Problem 89A

To determine

To calculate:

Maximum power handled by resistor.

Answer to Problem 89A

Maximum power handled by resistor is $69.4$ $\text{W}$ .

Explanation of Solution

Given:

  $\begin{array}{l}V=1.00\times {10}^2\text{V}\\ R=144\Omega \end{array}$

Formula Used:

  $P=IV$

  $V=IR$

Where,

  $V:$ Voltage

  $I:$ Current

  $R:$ Resistance

  $P:$ Power

Calculation:

Voltage is given by formula,

  $V=IR$

Rearranging the above formula,

  $I=\frac{V}{R}$

Maximum power handled by resistor can be calculated by formula,

  $P=IV$

Substituting the value of $I$ in the above formula,

  $P_{\max }=\left(\frac{V}{R}\right)V$

  $P_{\max }=\frac{V^2}{R}$

Substituting the values in above formula,

  $=\frac{{\left(1.00\times {10}^{\text{2}}\text{V}\right)}^2}{144}$

  = $69.4\text{W}$

Conclusion:

Hencemaximum power handled by resistor is $69.4\text{W}$ .