ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
4th Edition
ISBN: 9781119659587
Author: Klein
Publisher: WILEY
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Chapter 25, Problem 91IP
Interpretation Introduction
Interpretation:
Why the side chain of tryptophan is not considered as basic even though it has nitrogen with lone pair need to be explained.
Concept introduction:
Amino acids are compounds that have an
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6. Consider the following exothermic reaction below.
2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq)
a. If Cul is added, there will be a shift left/shift right/no shift (circle one).
b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one).
c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one).
d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle
one). Hint: one of the reaction species is more soluble in hexane than in water.
e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one).
f. Which of the changes above will change the equilibrium constant, K?
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Chapter 25 Solutions
ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG(LL)
Ch. 25.2 - Prob. 1CCCh. 25.2 - Prob. 2CCCh. 25.2 - Prob. 3CCCh. 25.2 - Prob. 1LTSCh. 25.2 - Prob. 4PTSCh. 25.2 - Prob. 7CCCh. 25.2 - Prob. 8CCCh. 25.2 - Prob. 9CCCh. 25.2 - Prob. 10CCCh. 25.2 - Prob. 11CC
Ch. 25.3 - Prob. 12CCCh. 25.3 - Prob. 13CCCh. 25.3 - Prob. 2LTSCh. 25.3 - Prob. 14PTSCh. 25.3 - Prob. 17CCCh. 25.3 - Prob. 18CCCh. 25.3 - Prob. 19CCCh. 25.3 - Prob. 20CCCh. 25.4 - Prob. 3LTSCh. 25.4 - Prob. 21PTSCh. 25.4 - Prob. 25CCCh. 25.4 - Prob. 26CCCh. 25.4 - Prob. 27CCCh. 25.4 - Prob. 28CCCh. 25.4 - Prob. 29CCCh. 25.5 - Prob. 30CCCh. 25.5 - Prob. 4LTSCh. 25.5 - Prob. 31PTSCh. 25.6 - Prob. 5LTSCh. 25.6 - Prob. 34PTSCh. 25 - Prob. 40PPCh. 25 - Prob. 41PPCh. 25 - Prob. 42PPCh. 25 - Prob. 43PPCh. 25 - Prob. 44PPCh. 25 - Prob. 45PPCh. 25 - Prob. 46PPCh. 25 - Prob. 47PPCh. 25 - Prob. 48PPCh. 25 - Prob. 49PPCh. 25 - Prob. 50PPCh. 25 - Prob. 51PPCh. 25 - Prob. 52PPCh. 25 - Prob. 53PPCh. 25 - Prob. 54PPCh. 25 - Prob. 55PPCh. 25 - Prob. 56PPCh. 25 - Prob. 57PPCh. 25 - Prob. 58PPCh. 25 - Prob. 59PPCh. 25 - Prob. 60PPCh. 25 - Prob. 61PPCh. 25 - Prob. 62PPCh. 25 - Prob. 63PPCh. 25 - Prob. 64PPCh. 25 - Prob. 65PPCh. 25 - Prob. 66PPCh. 25 - Prob. 67PPCh. 25 - Prob. 68PPCh. 25 - Prob. 69PPCh. 25 - Prob. 70PPCh. 25 - Prob. 71PPCh. 25 - Prob. 72PPCh. 25 - Prob. 73PPCh. 25 - Prob. 74PPCh. 25 - Prob. 75PPCh. 25 - Prob. 76PPCh. 25 - Prob. 77PPCh. 25 - Prob. 78PPCh. 25 - Prob. 79PPCh. 25 - Prob. 80PPCh. 25 - Prob. 81PPCh. 25 - Prob. 82PPCh. 25 - Prob. 83PPCh. 25 - Prob. 89IPCh. 25 - Prob. 90IPCh. 25 - Prob. 91IPCh. 25 - Prob. 92IP
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- 1. For each of the following statements, indicate whether they are true of false. ⚫ the terms primary, secondary and tertiary have different meanings when applied to amines than they do when applied to alcohols. • a tertiary amine is one that is bonded to a tertiary carbon atom (one with three C atoms bonded to it). • simple five-membered heteroaromatic compounds (e.g. pyrrole) are typically more electron rich than benzene. ⚫ simple six-membered heteroaromatic compounds (e.g. pyridine) are typically more electron rich than benzene. • pyrrole is very weakly basic because protonation anywhere on the ring disrupts the aromaticity. • thiophene is more reactive than benzene toward electrophilic aromatic substitution. • pyridine is more reactive than nitrobenzene toward electrophilic aromatic substitution. • the lone pair on the nitrogen atom of pyridine is part of the pi system.arrow_forwardThe following reactions are NOT ordered in the way in which they occur. Reaction 1 PhO-OPh Reaction 2 Ph-O -CH₂ heat 2 *OPh Pho -CH2 Reaction 3 Ph-O ⚫OPh + -CH₂ Reaction 4 Pho Pho + H₂C OPh + CHOPh H₂C -CH₂ Reactions 1 and 3 Reaction 2 O Reaction 3 ○ Reactions 3 and 4 ○ Reactions 1 and 2 Reaction 4 ○ Reaction 1arrow_forwardSelect all possible products from the following reaction: NaOH H₂O a) b) ОН HO O HO HO e) ОН f) O HO g) h) + OHarrow_forward
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