Organic Chemistry
Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 25, Problem 25.19P
Interpretation Introduction

Interpretation:

G' for ATP hydrolysis in a cell in which the concentrations of ATP, ADP, and phosphate are all 1 mM, is to be calculated.

Concept Introduction:

Hydrolysis of ATP produces ADP and phosphate. The standard free energy chain for this hydrolysis reaction is known. If the concentrations of the reactants and products are known, the G' can be calculated.

Expert Solution & Answer
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Answer to Problem 25.19P

G'= -48.29 kJmol-1

Explanation of Solution

The hydrolysis reaction of ATP is as follows:

ATP+H2O ADP+Phosphate

The G0' for this reaction is -30.5 kJmol-1

To calculate the G', the equation is

G'= G0'+2.3RTlogADP[phosphate][ATP]

The concentrations of ATP, ADP, and phosphate are all 1 mM, which is equal to 0.001 M.

The value of 2.3RT at 370C is 5.93 kJmol-1

Substituting all these values in the equation,

G'= G0'+2.3RTlogADP[phosphate][ATP]

G'= -30.5 kJmol-1+5.93 kJmol-1log0.001[0.001][0.001]

G'= -30.5 kJmol-1+5.93 kJmol-1(log0.001)

G'= -30.5 kJmol-1+5.93 kJmol-1(-3)

G'= -30.5 kJmol-1-17.79 kJmol-1

G'= -48.29 kJmol-1

Conclusion

The G' for the hydrolysis of ATP is -48.29 kJmol-1.

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