A high-voltage supply can be constructed from a variable capacitor with interleaving plates which can be rotated as in Fig. 24–36. A version of this type of capacitor with more plates has a capacitance which can be varied from 10 pF to 1 pF. ( a ) Initially, this capacitor is charged by a 7500-V power supply when the capacitance is 8.0 pF. It is then disconnected from the power supply and the capacitance reduced to 1.0 pF by rotating the plates. What is the voltage across the capacitor now? ( b ) What is a major disadvantage of this as a high-voltage power supply?
A high-voltage supply can be constructed from a variable capacitor with interleaving plates which can be rotated as in Fig. 24–36. A version of this type of capacitor with more plates has a capacitance which can be varied from 10 pF to 1 pF. ( a ) Initially, this capacitor is charged by a 7500-V power supply when the capacitance is 8.0 pF. It is then disconnected from the power supply and the capacitance reduced to 1.0 pF by rotating the plates. What is the voltage across the capacitor now? ( b ) What is a major disadvantage of this as a high-voltage power supply?
A high-voltage supply can be constructed from a variable capacitor with interleaving plates which can be rotated as in Fig. 24–36. A version of this type of capacitor with more plates has a capacitance which can be varied from 10 pF to 1 pF. (a) Initially, this capacitor is charged by a 7500-V power supply when the capacitance is 8.0 pF. It is then disconnected from the power supply and the capacitance reduced to 1.0 pF by rotating the plates. What is the voltage across the capacitor now? (b) What is a major disadvantage of this as a high-voltage power supply?
STRUCTURES I
Homework #1: Force Systems
Name:
TA:
PROBLEM 1
Determine the horizontal and vertical components of
the force in the cable shown.
PROBLEM 2
The horizontal component of force F is 30 lb. What is the
magnitude of force F?
6
10
4
4
F = 600lbs
F = ?
The determined Wile E. Coyote is out once more to try to capture the elusive Road Runner of Loony Tunes fame. The coyote is strapped to a rocket, which provide a constant horizontal acceleration of 15.0 m/s2. The coyote starts off at rest 79.2 m from the edge of a cliff at the instant the roadrunner zips by in the direction of the cliff. If the roadrunner moves with constant speed, find the minimum velocity the roadrunner must have to reach the cliff before the coyote. (proper sig fig)
Hello, I need some help with calculations for a lab, it is Kinematics: Finding Acceleration Due to Gravity. Equations: s=s0+v0t+1/2at2 and a=gsinθ. The hypotenuse,r, is 100cm (given) and a height, y, is 3.5 cm (given). How do I find the Angle θ1? And, for distance traveled, s, would all be 100cm? For my first observations I recorded four trials in seconds: 1 - 2.13s, 2 - 2.60s, 3 - 2.08s, & 4 - 1.95s. This would all go in the coloumn for time right? How do I solve for the experimental approximation of the acceleration? Help with trial 1 would be great so I can use that as a model for the other trials. Thanks!
Chapter 24 Solutions
Physics for Scientists and Engineers with Modern Physics
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How To Solve Any Circuit Problem With Capacitors In Series and Parallel Combinations - Physics; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=a-gPuw6JsxQ;License: Standard YouTube License, CC-BY