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Interpretation: An enzyme-substrate complex and its formation have to be explained.
Concept introduction: Enzymes are present in every living thing. Enzymes are proteins that catalyze the biochemical reactions that occur in living organisms.
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Answer to Problem 56A
The non-covalent complex is known as the enzyme-substrate complex. It is formed when an enzyme attaches to a substrate to catalyze the biochemical process.
Explanation of Solution
An enzyme and its substrate form a non-covalent complex that is called the enzyme-substrate complex. This complex consists of a substrate that is attached to the active site of an enzyme.
When an enzyme binding to a substrate to catalyze the biochemical process, an enzyme-substrate complex is formed. An enzyme's active site is contacted and bound by a substrate. This reaction converts the substrate into products by forming an enzyme product complex. After then, the enzyme's active site releases the products.
The non-covalent complex is known as the enzyme-substrate complex. It is formed when an enzyme attaches to a substrate to catalyze the biochemical process.
Chapter 24 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Bookmarks Profiles Tab Window Help Chemical Formula - Aktiv Che X + → C 11 a app.aktiv.com Google Chrome isn't your default browser Set as default Question 12 of 16 Q Fri Feb 2 Verify it's you New Chrome availabl- Write the balanced molecular chemical equation for the reaction in aqueous solution for mercury(I) nitrate and chromium(VI) sulfate. If no reaction occurs, simply write only NR. Be sure to include the proper phases for all species within the reaction. 3 Hg(NO3)2(aq) + Cг2(SO4)3(aq) → 3 Hg₂SO (s) + 2 Cr(NO3), (aq) ean Ui mate co ence an climate bility inc ulnerabili women, main critic CLIMATE-INI ernational + 10 O 2 W FEB 1 + 4- 3- 2- 2 2 ( 3 4 NS 28 2 ty 56 + 2+ 3+ 4+ 7 8 9 0 5 (s) (1) Ch O 8 9 (g) (aq) Hg NR CI Cr x H₂O A 80 Q A DII A F2 F3 FA F5 F6 F7 F8 F9 #3 EA $ do 50 % 6 CO & 7 E R T Y U 8 ( 9 0 F10 34 F11 川 F12 Subr + delete 0 { P }arrow_forwardDeducing the reactants of a Diels-Alder reaction n the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. >arrow_forwardPredict the major products of the following organic reaction: + Some important notes: A ? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure.arrow_forward
- if the answer is no reaction than state that and please hand draw!arrow_forward"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardreciprocal lattices rotates along with the real space lattices of the crystal. true or false?arrow_forwardDeducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forward
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