(a)
Interpretation: The biological molecule has to be identified.
Concept Introduction: The most vital organic molecules,
(a)
Answer to Problem 81A
The given biological molecule is triglyceride.
Explanation of Solution
The major type of biological molecules are carbohydrates, lipids,
The given biological molecule is triglyceride.
It is characterized by a glycerol backbone attached to 33 fatty acid chains.
Three molecules of one or more distinct fatty acids are bonded to the alcohol glycerol to form triglycerides, which are esters.
The tissues can use fatty acids for energy production or they can be stored as energy in the form of triglycerides.
In response to energy needs, the stored triglycerides are broken down, and the unsaturated fatty acids are then released into the bloodstream and supplied to the tissues.
(b)
Interpretation: The biological molecule has to be identified.
Concept Introduction: The most vital organic molecules, biomolecules are engaged in the maintenance and metabolic functions of living things. These inert molecules are the true foot soldiers in the fight for life's nourishment.
(b)
Answer to Problem 81A
The given biological molecule is glucose.
Explanation of Solution
The major type of biological molecules are carbohydrates, lipids, nucleic acids, and proteins.
The given biological molecule belongs to carbohydrates.
It is glucose, a monosaccharide.
A class of chemical substances known as carbohydrates can be found in foods and living tissues as starch, cellulose, and sugars.
(c)
Interpretation: The biological molecule has to be identified.
Concept Introduction: The most vital organic molecules, biomolecules are engaged in the maintenance and metabolic functions of living things. These inert molecules are the true foot soldiers in the fight for life's nourishment.
(c)
Answer to Problem 81A
The given biological molecule is dipeptide.
Explanation of Solution
The major type of biological molecules are carbohydrates, lipids, nucleic acids and proteins.
The given biological molecule is a dipeptide.
There is the presence of amide and
In nature, amide bonds hold together short chains of amino acid monomers to form peptides.
Chapter 24 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- For each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardThe following reaction is run in which the initial conditions include only methane (CH4) at a concentration of0.115 M. Once equilibrium was established, the concentration of acetylene (C2H2) was measured to be 0.035M. What is the value of the equilibrium constant, K?2 CH4 (g) ⇋ C2H2 (g) + 3 H2 (g)arrow_forwardCalculate the equilibrium concentration of carbon dioxide for the following reaction:2 COF2 (g) ⇋ CF4 (g) + CO2 (g) Kc = 2.00 at 10.00 °C. at equilibrium [COF2] = 0.255M; [CF4] = 0.118Marrow_forward
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- Indicate the compound resulting from adding NaOH cyclopentane-CH2-CHO.arrow_forwardUse the provided information to calculate Kc for the following reaction at 550 °C: H2(g) + CO2(g) ⇌ CO(g) + H2O(g) Kc = ?CoO(s) + CO(g) ⇌ Co(s) + CO2(g) Kc1 = 490CoO(s) + H2(g) ⇌ Co(s) + H2O(g) Kc2 = 67arrow_forwardCalculate Kc for the reaction: I2 (g) ⇋ 2 I (g) Kp = 6.26 x 10-22 at 298Karrow_forward
- For each scenario below, select the color of the solution using the indicator thymol blue during the titration. When you first add indicator to your Na2CO3solution, the solution is basic (pH ~10), and the color is ["", "", "", "", ""] . At the equivalence point for the titration, the moles of added HCl are equal to the moles of Na2CO3. One drop (or less!) past this is called the endpoint. The added HCl begins to titrate the thymol blue indicator itself. At the endpoint, the indicator color is ["", "", "", "", ""] . When you weren't paying attention and added too much HCl (~12 mL extra), the color is ["", "", "", "", ""] . When you really weren't paying attention and reached the second equivalence point of Na2CO3, the color isarrow_forwardTo convert cyclopentane-CH2-CHO to cyclopentane-CH2-CH3, compound A is added, followed by (CH3)3CO-K+, DMS at 100oC. Indicate which compound A is.arrow_forwardIndicate how to obtain the compound 2-Hydroxy-2-phenylacetonitrile from phenylmethanol.arrow_forward
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