
(a)
Interpretation: Need to mention the
Concept Introduction: A polymer is formed by joining a large number of macromolecules that are known as monomers. A polymer is composed of repeating monomeric units that are bonded together.
(a)

Answer to Problem 103A
The polymer formed from amino acids is protein.
Explanation of Solution
Amino acids are the smaller molecules that make up a protein. The molecules of amino acids are composed of carbon, nitrogen, hydrogen, and oxygen. There are
Every amino acid consists of two
When two amino acids combine, they release a water molecule along with the formation of protein via a condensation reaction. The bond that links amino acid units together is known as a peptide bond.
(b)
Interpretation: Need to mention the polymer formed from the given monomer.
Concept Introduction: A polymer is formed by joining a large number of macromolecules that are known as monomers. A polymer is composed of repeating monomeric units that are bonded together.
(b)

Answer to Problem 103A
The polymer formed from a monosaccharide is a polysaccharide.
Explanation of Solution
The simplest carbohydrates are known as monosaccharides. They are also called simple sugars. It serves as a monomeric unit for the formation of polysaccharides as they cannot be broken down into simpler units/sugars.
On joining many monosaccharide units together, the polymer so formed is a polysaccharide, and if two monosaccharide units are joined together, it yields the formation of a disaccharide.
(c)
Interpretation: Need to mention the polymer formed from the given monomer.
Concept Introduction: A polymer is formed by joining a large number of macromolecules that are known as monomers. A polymer is composed of repeating monomeric units that are bonded together.
(c)

Answer to Problem 103A
The polymer formed from a
Explanation of Solution
An unbranched polymer that is made up of nucleotides (that serve as monomeric units) is known as nucleic acid. The nucleotide is a combination of sugar, phosphate, and base.
DNA and RNA molecules are basically
Chapter 24 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Calculating the pH at equivalence of a titration Try Again Your answer is incorrect. 0/5 a A chemist titrates 70.0 mL of a 0.7089 M hydrocyanic acid (HCN) solution with 0.4574M KOH solution at 25 °C. Calculate the pH at equivalence. The pK of hydrocyanic acid is 9.21. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of KOH solution added. pH = 11.43] G 00. 18 Ar B•arrow_forwardBiological Macromolecules Naming and drawing the products of aldose oxidation and reduction aw a Fischer projection of the molecule that would produce L-ribonic acid if it were subjected to mildly oxidizing reaction conditions. Click and drag to start drawing a structure. X AP ‡ 1/5 Naor Explanation Check McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibilarrow_forward● Biological Macromolecules Identifying the parts of a disaccharide Take a look at this molecule, and then answer the questions in the table below it. CH2OH O H H H OH OH OH H H CH2OH H O OH H OH H H H H OH Is this a reducing sugar? Does this molecule contain a glycosidic bond? If you said this molecule does contain a glycosidic bond, write the symbol describing it. If you said this molecule does contain a glycosidic bond, write the common names (including anomer and enantiomer labels) of the molecules that would be released if that bond were hydrolyzed. If there's more than one molecule, separate each name with a comma. Explanation Check O yes X O no ○ yes O no Uarrow_forward
- The aim of the lab is to measure the sodium content from tomato sauce using the Mohr titration method. There are two groups being: Regular Tomato sauce & Salt Reduced tomato sauce QUESTION: State how you would prepare both Regular & Salt reduced tomato sauce samples for chemical analysis using the Mohr titration methodarrow_forwardUsing the conditions of spontaneity to deduce the signs of AH and AS Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A The reverse of this reaction is always spontaneous but proceeds faster at temperatures above -48. °C. ΔΗ is (pick one) ✓ AS is (pick one) B This reaction is spontaneous except below 114. °C but proceeds at a slower rate below 135. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is C This reaction is exothermic and proceeds faster at temperatures above -43. °C. (pick one) AS is (pick one) v Х 5 ? 18 Ararrow_forwardion. A student proposes the following Lewis structure for the perchlorate (CIO) io : :0: : Cl : - - : :0: ك Assign a formal charge to each atom in the student's Lewis structure. atom central O formal charge ☐ top O ☐ right O ☐ bottom O ☐ Cl ☐arrow_forward
- Decide whether these proposed Lewis structures are reasonable. proposed Lewis structure Yes. Is the proposed Lewis structure reasonable? Cl- : 2: :Z: :Z: N—N : 0: C C1: O CO No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* ☐ Yes. No, it has the wrong number of valence electrons. The correct number is: ☐ No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are:* | If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0". ☑arrow_forwardUse the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions ΔΗ is (pick one) A This reaction is faster above 103. °C than below. AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous only above -9. °C. AS is (pick one) ΔΗ is (pick one) C The reverse of this reaction is always spontaneous. AS is (pick one) 18 Ararrow_forwardUse the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A The reverse of this reaction is always spontaneous but proceeds slower at temperatures below 41. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous except above 94. °C. AS is (pick one) This reaction is always spontaneous, but ΔΗ is (pick one) C proceeds slower at temperatures below −14. °C. AS is (pick one) Х 00. 18 Ar 무ㅎ B 1 1arrow_forward
- Draw the product of the reaction shown below. Ignore inorganic byproducts. + H CH3CH2OH HCI Drawingarrow_forwardplease explain this in simple termsarrow_forwardK Most Reactive Na (3 pts) Can the metal activity series (shown on the right) or a standard reduction potential table explain why potassium metal can be prepared from the reaction of molten KCI and Na metal but sodium metal is not prepared from the reaction of molten NaCl and K metal? Show how (not). Ca Mg Al с Zn Fe Sn Pb H Cu Ag Au Least Reactivearrow_forward
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